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bekas [8.4K]
3 years ago
5

Find the value of x. (14x – 13) (8x + 5)

Mathematics
1 answer:
Sati [7]3 years ago
4 0

Answer:

x = 3 (I think)

Step-by-step explanation:

14x - 13 = 8x + 5 (I'm assuming the two expressions are equal)

6x - 13 = 5

6x = 18

x = 3

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judi is making a rope ladder. she uses 1/2 yard of rope for each step. how many steps can she make with 6 yards of rope? show yo
Veseljchak [2.6K]

Answer:

12 steps.

Step-by-step explanation:

6 / (1/2)

= 12 steps

Hope this helped!

7 0
3 years ago
Read 2 more answers
5/4+x=3/4 how do I figure this out
Andreyy89

You could subtract 5/4 from each side of the equation.
Then it would say
                                 x = -2/4 .

That's a perfectly true solution, but not a very attractive one.
To pretty it up, you could simplify the fraction if you felt like it,
and you would have
                                   x = -1/2 .

4 0
3 years ago
Bitsy Betsy is only 4 and half feet tall. How many inches is she?
max2010maxim [7]

Answer:

54 inches

Step-by-step explanation:

first you're going to want to put four and a half feet into a decimal (4.5) and multiply it by how many inches are in 1 ft ( 12). after that you're going to want to count how many decimal paces there are (2) and move your decimal at the end of 5400 to 54.00. The extra 0s are not needed.

7 0
2 years ago
Read 2 more answers
A right rectangular prism is packed with cubes of side length fraction 1 over 2 inch. If the prism is packed with 5 cubes along
IgorLugansk [536]

Answer:

It will be 3 and 3 over 4 cubic inches

Step-by-step explanation:

5 0
3 years ago
Please help me out please
natita [175]

Answer:

RC = 40

Step-by-step explanation:

Note that the circumcentre is equally distant from the triangle's 3 vertices.

That is : PC = RC = QC

Equate any pair and solve for x

Using RC = PC, then

5x - 15 = 3x + 7 ( subtract 3x from both sides )

2x - 15 = 7 ( add 15 to both sides )

2x = 22 ( divide both sides by 2 )

x = 11

Hence

RC = (5 × 11) - 15 = 55 - 15 = 40 units

5 0
3 years ago
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