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2 years ago

Which range is the approximate audible range for humans?

Physics

2 answers:

allsm [11]2 years ago

8 0

Answer:

Explanation:

bcz mre than that they will be affected

nlexa [21]2 years ago

6 0

$\triangleright$ $\overline{\qquad{\qquad{\qquad{\qquad{\qquad{\qquad{\qquad{\qquad}}}}}}}}$ $\triangleleft$

$\boldsymbol{Answer.}$

$\bullet$ Option [A].

$\triangleright$ $\overline{\qquad{\qquad{\qquad{\qquad{\qquad{\qquad{\qquad}}}}}}}$ $\triangleleft$

$\boldsymbol{Explanation.}$

Hi student! Let me help you out on this question.

The approximate audible range for humans is.

$\boldsymbol{20-20,000\:Hertz\,(Hz)}$ .

Humans can't hear sounds lower than 20 Hz or higher than 20,000 Hz.

$\boldsymbol{\therefore,\:Option\:\big[A\big]\,is\,correct.}$

Hope that this helped you out! Best wishes!

$\star\triangleright\boldsymbol{Reach\:far.\,Aim\,high.\,Dream\,big.}\triangleleft\star$

$\ddagger\it{-Greetings!-}\dagger$

_______________________

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Much power does a 10 Ohm bulb have in a series circuit with a battery of 12V and nothing else in the the circuit?

Sedaia [141]

Answer:

it will be d) 14.4W

Explanation:

potential difference (v) = 12 volts

resistance (r) = 10 ohms

now, we know

=》

$power = \frac{v {}^{2} }{r}$

=》

$power \: = \frac{12 {}^{2} }{10}$

=》

$power = \frac{144}{10}$

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8 0

2 years ago

Prove the correctness of this equation s=vt + 1/2at

Kaylis [27]

Answer:

The formula is dimensionally correct.

Explanation:

Given

$s = ut + \frac{1}{2}at^2$

Required

Prove its correctness

Write out the dimension of each:

$s = M^0LT^0$ --- displacement

$ut = M^0LT^{-1} * T$ --- velocity * time

$\frac{1}{2}at^2 = M^0LT^{-2} * T^2$ --- acceleration * square of time

The expression becomes:

$s = ut + \frac{1}{2}at^2$

$M^0LT^0 = M^0LT^{-1} * T + M^0LT^{-2} * T^2$

Apply law of indices

$M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}$

$M^0LT^0 = M^0LT^{0} + M^0LT^{0}$

$M^0LT^0 = M^0LT^{0}$

Both sides of the equation are equal

5 0

2 years ago

Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 1.4×109 electrons from one disk to the

allsm [11]

Answer:

r = 6.5*10^-3 m

Explanation:

I'm assuming you meant to ask the diameters of the disk, if so, here's it

Given

Quantity of charge on electron, Q = 1.4*10^9

Electric field strength, e = 1.9*10^5

q = Q * 1.6*10^-19

q = 2.24*10^-10

E = q/ε(0)A, making A the subject of formula, we have

A = q / [E * ε(0)], where

ε(0) = 8.85*10^-12

A = 2.24*10^-10 / (1.9*10^5 * 8.85*10^-12)

A = 2.24*10^-10 / 1.6815*10^-6

A = 1.33*10^-4 m²

Remember A = πr²

1.33*10^-4 = 3.142 * r²

r² = 1.33*10^-4 / 3.142

r² = 4.23*10^-5

r = 6.5*10^-3 m

3 0

3 years ago

A motorcycle has a mass of 350kg. A force of 1295N is applied to the cycle what is the motorcycles acceleration

Maru [420]

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Explanation:

The acceleration of the motorcycle is given by Newton's second law:

$a=\frac{F}{m}$

where

F = 1295 N is the force applied to the motorcycle

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a is the acceleration

By substituting the numbers into the formula, we find

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4 0

3 years ago

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Explanation:

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2 years ago