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kozerog [31]
3 years ago
5

This is due by 11:59 PM tonight.

Physics
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:

1. increases

2. increases

3. increases

Explanation:

Part 1:

First of all, since the box remains at rest, the horizontal net force acting on the box must equal zero:

F1 - fs = 0.

And this friction force fs is:

fs = Nμs,

where μs is the static coefficient of friction, and N is the normal force.

Originally, the normal force N is equal to mg, where m is the mass of the box, and g is the constant of gravity. Now, there is an additional force F2 acting downward on the box, which means it increases the normal force, since the normal force by Newton's third law, is the force due to the surface acting on the box upward:

N = mg + F2.

So, F2 is increasing, that means fs is increasing too.

Part 2:

As explained in the part 1, N = mg + F2. F2 is increasing, so the normal force is thus increasing.

Part 3:

In part 1 and part 2, we know that fs = Nμs, and since the normal force N is increasing, the maximum possible static friction force fs, max is also increasing.

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Water has a very high specific heat capacity when compared to most other common materials. In fact, ethyl alcohol has a specific
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Answer:

Lead, Ethyl alcohol and water.

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3 years ago
Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
gtnhenbr [62]

Answer:

"2Ω" is the net resistance in the circuit.

Explanation:

The given resistors are:

R1 = 3Ω

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The net resistance will be:

⇒  \frac{1}{R_{net}} =\frac{1}{R_1} +\frac{1}{R_2}

On substituting the values, we get

⇒  \frac{1}{R_{net}} =\frac{1}{3} +\frac{1}{6}

On taking L.C.M, we get

⇒  \frac{1}{R_{net}} =\frac{2+1}{6}

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⇒  \frac{1}{R_{net}} =\frac{1}{2}

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⇒ R_{net}=2 \Omega

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2 years ago
I really need Brainliest i am desprate
kondor19780726 [428]

Hy tikki! I've asked some questions, so of you find the questions as easy, then answer it. I'll surely mark you as brainliest :)

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Any help????????????
pashok25 [27]
The answer should be D
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The answer is c. 
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