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Masja [62]
3 years ago
5

What is the electron configuration of the calcium ion?

Chemistry
1 answer:
olga2289 [7]3 years ago
3 0
The electron configuration Is [AR]4s2
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Density measurements were conducted on a 22.5oC sample of water which had a theoretical density of 0.997655 g/ml. A volume of 10
Sophie [7]

Let's divide the three experiments: The experiment with 10.00 mL of water is A), the experiment with 15.00 mL is B), and the experiment with 25.00 mL is C).

  • (1) Now let's calculate the experimental density of each experiment. Density (ρ) is equal to the mass divided by the volume, thus:

p_{A} =9.98g/10.00mL=0.998g/mL\\p_{B} =15.61g/15.00mL=1.041g/mL\\p_{C} =25.65g/25.00mL=1.026g/mL

  • (2)To calculate the average density, we add each density and divide the result by the number of experiments (in this case 3):

p_{average}=\frac{p_{1}+p_{2}+p_{3}}{3}   \\p_{average}=\frac{(0.998+1.041+1.026)g/mL}{3}\\p_{average}=1.022g/mL

  • (3) The percent error is calculated by dividing the absolute value of the substraction of the theorethical and experimental values, by the theoretical value, times 100:

%error=\frac{|p_{average}-p_{theoretical}|}{p_{theoretical}} *100

%error=\frac{|1.022g/mL-0.997655g/mL|}{0.997655g/mL}*100

%error=2.44 %

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Heat required to raise 1 g of a substance 1°C
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How many resonance structures can be drawn for N2O5 (no N-N bond) (minimal formal charge)?
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There are approximately 4 resonance structures that can be drawn for N205 (no N-N bond) (minimal formal charge). 
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Convert 9.90km to mm
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2.13 x 10 E 7 i believe this is correct
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