Answer:
25.0 mL
Explanation:
1. Gather the information in one place.
MM: 98.00 74.09
2H3PO4 + 3Ca(OH)2 → Ca3(PO4)2 + 6H2O
m/g: 8.85 15.76
V/mL: 350.0 550
2. Moles of H3PO4
n = 8.85 g × (1 mol/98.00 g) = 0.09031 mol H3PO4
3. Moles of Ca(OH)2
n = 15.76 g × (1 mol/74.09 g) = 0.2126 mol Ca(OH)2
4. Moles of Ca(OH)2 in 25.0 mL Solution
n = 0.2126 mol × (25.0 mL/550 mL) = 0.009 663 mol Ca(OH)2
5. Moles of H3PO4 needed
From the balanced equation, the molar ratio is 2 mol H3PO4: 3 mol Ca(OH)2
n = 0.009 663 mol Ca(OH)2 × (2 mol H3PO4/3 mol Ca(OH)2)
= 0.006 442 mol H3PO4
6. Volume of H3PO4
V = 0.006 442 mol ×( 350.0 mL/0.09031 mol) = 25.0 mL H3PO4
It will take 25.0 mL of the H3PO4 solution to neutralize 25.0 mL of the Ca(OH)2 solution.
Answer: A light bulb in the same room at the same temperature.
Explanation: Yw, BYE!!!
Answer:
0.0069 mol
Explanation:
Given data:
Temperature = 25°C
Volume of gas = 0.044 L
Pressure of gas = 3.81 atm
Number of moles of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273 = 298 K
3.81 atm × 0.044 L = n × 0.0821 atm.L/ mol.K × 298 K
0.17 atm.L = n ×24.47 atm.L/ mol
n = 0.17 atm.L/24.47 atm.L/ mol
n = 0.0069 mol
just say this: the green color is from the mold
