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2 years ago

PLEASE HELP ME!!!

Chemistry

1 answer:

kondor19780726 [428]2 years ago

6 0

<h3>Answer:</h3>

0.424 J/g °C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Chemistry</u>

<u>Thermochemistry</u>

Specific Heat Formula: q = mcΔT

q is heat (in Joules)
m is mass (in grams)
c is specific heat (in J/g °C)
ΔT is change in temperature

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] m = 38.8 g

[Given] q = 181 J

[Given] ΔT = 36.0 °C - 25.0 °C = 11.0 °C

[Solve] c

<u>Step 2: Solve for Specific Heat</u>

Substitute in variables [Specific Heat Formula]: 181 J = (38.8 g)c(11.0 °C)
Multiply: 181 J = (426.8 g °C)c
[Division Property of Equality] Isolate <em>c</em>: 0.424086 J/g °C = c
Rewrite: c = 0.424086 J/g °C

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.424086 J/g °C ≈ 0.424 J/g °C

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