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3 years ago

Do sound waves always travel in straight lines explain

1 answer:

3 0

They travel like waves. Just throw rock at lake you will see wave. When it bumps to barrier barrier reflects some part of it . Not like a line lika a wave

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A 35 g block of ice is cooled to −83 ◦C. It is added to 565 g of water in an 87 g copper calorimeter at a temperature of 22◦C. F

Tcecarenko [31]

Answer:

Explanation:

Heat gained by ice in warming up to 0⁰C = .035 x 2090 x (83-0)= 6071.45 J

heat used up by ice to melt at 0⁰C = .035 x 3.33 x 10⁵ J = 11655 J

Heat used up in warming up water to t⁰C = .035 x 4186 x t = 146.51 t

heat released by warm water to cool from 22⁰C to t = .565 x 4186 x ( 22 - t )

=52032 -2365.1 t

heat released by copper calorimeter to cool from 22⁰C to t = .087 x 387 x ( 22 - t ) = 740.72 - 33.7 t

total heat released = 52032 -2365.1 t + 740.72 - 33.7 t

= 52772.72 - 2398.8 t

Heat lost = heat gained

52772.72 J- 2398.8 t = 6071.45 J + 11655 J + 146.51 t

2545.31 t = 35046.27

t = 13.8°C.

7 0

3 years ago

Explain Using the equation for translational kinetic energy, show why a car moving at 40 m/s has four times the translational ki

djverab [1.8K]

Answer:

Explanation:

Equation for translational kinetic energy = 1/2 m V² where m is mass and V is velocity .

In first case let mass of car be m

Translational kinetic energy = 1/2 m x 40² = 800 m .

In the second case ,

Translational kinetic energy = 1/2 m x 20² = 200 m

So , in former case kinetic energy of car is 4 times that of second case.

7 0

3 years ago

How do I spell pineapple apple pen

Aliun [14]

Answer:

ppap

Explanation:

idk man :vvvv. v vv.

6 0

3 years ago

Ur a genius if u explain how it’s A correctly

Alinara [238K]

Answer:

Explanation:

4/1=4

3/2=1.5

2/3=0.666667

1/4=0.25

D has the least number so its D

6 0

3 years ago

What is the pressure drop due to the bernoulli effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire

Paul [167]

Answer:

$\Delta P=1581357.92\ Pa$

Explanation:

Given:

diameter of hose pipe, $D=0.09\ m$

diameter of nozzle, $d=0.03\ m$

volume flow rate, $\dot{V}=40\ L.s^{-1}=0.04\ m^3.s^{-1}$

<u>Now, flow velocity in hose:</u>

$v_h=\frac{\dot V}{\pi.D^2\div 4}$

$v_h=\frac{0.04\times 4}{\pi\times 0.09^2}$

$v_h=6.2876\ m.s^{-1}$

<u>Now, flow velocity in nozzle:</u>

$v_n=\frac{\dot V}{\pi.d^2\div 4}$

$v_n=\frac{0.04\times 4}{\pi\times 0.03^2}$

$v_n=56.5884\ m.s^{-1}$

We know the Bernoulli's equation:

$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}+Z_1=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}+Z_2$

when the two points are at same height then the eq. becomes

$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}$

$\Delta P=\frac{\rho(v_n^2-v_h^2)}{2}$

$\Delta P=\frac{1000(56.5884^2-6.2876^2)}{2}$

$\Delta P=1581357.92\ Pa$

8 0

3 years ago