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2 years ago

The zero tolerance law applies to drivers _________.

Physics

1 answer:

s2008m [1.1K]2 years ago

4 0

The zero tolerance law applies to drivers under the age of 21.

<h3>Zero Tolerance Law:</h3>

Drivers under the age of 21 who operate a motor vehicle with a BAC of between 0.02% and 0.07% are subject to what is known as the "Zero Tolerance Law." The Zero Tolerance Law aims to prevent underage drivers from driving after consuming alcohol.

The zero-tolerance rule states that it is against the law for anyone under the age of 21 to operate a motor vehicle while having any detectable level of alcohol in their system. Zero Tolerance Law states that a minor has committed the criminal offense of DUI if there is ANY detectable level of alcohol in his or her system while operating a vehicle in public. The minor's driver's license is immediately suspended, and the officer has the authority to confiscate the license on the spot.

Learn more about zero tolerance here:

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Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by

mylen [45]

Answer:

I must travel with a speed of 2.97 x 10^8 m/s

Explanation:

Sine the spacecraft flies at the same speed in the to and fro distance of the journey, then the time taken will be 6 months plus 6 months

Time that elapses on the spacecraft = 1 year

On earth the people have advanced 120 yrs

According to relativity, the time contraction on the spacecraft is gotten from

$t$ = $t_{0} /\sqrt{1 - \beta ^{2} }$

where

$t$ is the time that elapses on the spacecraft = 120 years

$t_{0}$ = time here on Earth = 1 year

$\beta$ is the ratio v/c

where

v is the speed of the spacecraft = ?

c is the speed of light = 3 x 10^8 m/s

substituting values, we have

120 = 1/ $\sqrt{1 - \beta ^{2} }$

squaring both sides of the equation, we have

14400 = 1/ $(1 - \beta ^{2} )$

14400 - 14400 $\beta ^{2}$ = 1

14400 - 1 = 14400 $\beta ^{2}$

14399 = 14400 $\beta ^{2}$

$\beta ^{2}$ = 14399/14400 = 0.99

$\beta = \sqrt{0.99}$ = 0.99

substitute β = v/c

v/c = 0.99

but c = 3 x 10^8 m/s

v = 0.99c = 0.99 x 3 x 10^8 = 2.97 x 10^8 m/s

6 0

3 years ago

Helppp please i think I know the answer but i want to be sure

Vadim26 [7]

Answer: D) 0-3 seconds

Explanation:

5 0

1 year ago

Is the momentum of a 0.1 kg Mass moving with a velocity of 5 miles per second West

dem82 [27]

Momentum equals Mass x Velocity
Mass equals 0.1kg
Velocity equals 5m/s

So the momentum has to = 0.1 x 5 = 0.5kgm/s

I hope this helped

6 0

3 years ago

Read 2 more answers

A magnetic field is entering into a coil of wire with radius of 2(mm) and 200 turns. The direction of magnetic field makes an an

frozen [14]

Answer:

a) 2.278 x 10^-5 volts

b) 1.139 x 10^-6 Ampere

c) 2.59 x 10^-11 W

Explanation:

The radius of the wire r = 2 mm = 0.002 m

the number of turns N = 200 turns

direction of the magnetic field ∅ = 25°

magnetic field strength B = 0.02 T

varying time = 2 sec

The cross sectional area of the wire = $\pi r^{2}$

==> A = 3.142 x $0.002^{2}$ = 1.257 x 10^-5 m^2

Field flux Φ = BA cos ∅ = 0.02 x 1.257 x 10^-5 x cos 25°

==> Φ = 2.278 x 10^-7 Wb

The induced EMF is given as

E = NdΦ/dt

where dΦ/dt = (2.278 x 10^-7)/2 = 1.139 x 10^-7

E = 200 x 1.139 x 10^-7 = 2.278 x 10^-5 volts

b) If the two ends are connected to a resistor of 20 Ω, the current through the resistor is given as

$I$ = E/R

where R is the resistor

$I$ = (2.278 x 10^-5)/20 = 1.139 x 10^-6 Ampere

c) power delivered to the resistor is given as

P = $I$ E

P = (1.139 x 10^-6) x (2.278 x 10^-5) = 2.59 x 10^-11 W

4 0

3 years ago

A child is swinging back and forth with a constant period and amplitude. Somewhere in front of the child, a stationary horn is e

Amanda [17]

Answer:

Explanation:

We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .

f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .

f will be lowest when v₀ is highest .

velocity of observer is highest when he is at the equilibrium position or at middle point .

So apparent frequency is lowest when observer is at the middle point and going away from the source while swinging to and from before the source of sound .

3 0

3 years ago