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2 years ago

The zero tolerance law applies to drivers _________.

Physics

1 answer:

s2008m [1.1K]2 years ago

4 0

The zero tolerance law applies to drivers <u>under the age of 21.</u>

<h3>Zero Tolerance Law:</h3>

Drivers under the age of 21 who operate a motor vehicle with a BAC of between 0.02% and 0.07% are subject to what is known as the "Zero Tolerance Law." The Zero Tolerance Law aims to prevent underage drivers from driving after consuming alcohol.

The zero-tolerance rule states that it is against the law for anyone under the age of 21 to operate a motor vehicle while having any detectable level of alcohol in their system. Zero Tolerance Law states that a minor has committed the criminal offense of DUI if there is ANY detectable level of alcohol in his or her system while operating a vehicle in public. The minor's driver's license is immediately suspended, and the officer has the authority to confiscate the license on the spot.

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1. The spring in a trampoline has been stretched 0.25m and has a spring

nata0808 [166]

Answer:

250/0.25. * 0.25 =250J

Explanation:

PE=Force*displacement

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3 years ago

2. Compare the names of the metal elements by themselves to their names what they are part of andows

steposvetlana [31]

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3 years ago

A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.45 m/s^2 for 20.0 s.

Anton [14]

Answer:

a) The total displacement of the trip was 5.32 × 10³ m

b) The average speeds were:

leg 1: 24.5 m/s

leg 2: 49 m/s

leg 3: 23.9 m/s

Complete trip: 43.8 m/s

Explanation:

The position and velocity equations for an object moving along a straight line are as follows:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where

x = position at time t

x0 = initial position

v0 = initial velocity

t = time

a = acceleration

v = velocity at time t

If the velocity is constant, then a = 0 and x = x0 + v · t where "v" is the velocity.

a) To calculate the total displacement of the trip, let´s calculate the distance traveled in each phase.

Phase 1:

x = x0 + v0 · t + 1/2 · a · t²

x = 0 m + 0 m/s · t + 1/2 · 2.45 m/s² · (20.0 s)²

x = 490 m

The velocity reached in that phase is:

v = v0 + a · t

v = 0 m/s + 2.45 m/s² · 20.0 s

v = 49.0 m/s

Phase 2:

x = x0 + v · t

x = 490 m + 49.0 m/s · 96.0 s

x = 5.19 × 10³ m

Phase 3:

x = x0 + v0 · t + 1/2 · a · t²

x = 5.19 × 10³ m + 49 m/s · 5.44 s - 1/2 · 9.00 m/s² · (5.44 s)²

x = 5.32 × 10³ m

The total displacement of the trip was 5.32 × 10³ m

b) The average speed is calculated as the traveled distance divided by the elapsed time:

average speed v = final position - initial position / (final time- initial time)

Phase 1:

v = 490 m - 0 m / 20.0 s = 24.5 m/s

Phase 2:

v = 5.19 × 10³ m - 490 / 96.0 s

v = 48.9 m/s (without rounding the final position the result is 49.0 m/s)

Phase 3:

v = 5.32 × 10³ m - 5.19 × 10³ m / 5.44 s = 23.9 m/s

For the complete trip:

v = 5.32 × 10³ m - 0 m / (20.0 s + 96.0 s + 5.44 s)

v = 43.8 m/s

7 0

4 years ago

ListenA person weighing 6.0 × 102 newtons rides an elevator upward at an average speed of 3.0 meters per second for 5.0 seconds.

pychu [463]

Answer:

(d) 9 × 10^{3] J

Explanation:

from the question we are given the following:

weight of the man = 6.0 × 10 ^ {2} N

average speed (v) = 3 m/s

time (t) = 3 s

potential energy (U) = ?

We can calculate the increase in potential energy of the man by applying the formula below

increase in potential energy = P₂ - P₁

where

P₁ is the initial potential energy

P₂ is the final potential energy

Potential energy = mass x acceleration due to gravity x height

From physic we know that weight = mass x acceleration due to gravity

We should take note that the distance in this case is also our height, and we can get it from the formula distance = velocity x time

Distance = 3 x 5 = 15 meters
Initial potential energy P₁ is zero because the person was initially in motion and potential energy is the energy at rest.

therefore

potential energy = 6.0 × 10 ^ {2} × 15 = 9 × 10^{3] J

4 0

4 years ago

The position of a car at time t is given by the function p(t)=t2 2t−4. What is the velocity when p(t)=11? assume t≥0

AysviL [449]

The velocity when function p(t)=11 is 8 .

According to the question

The position of a car at time t represented by function :

$p(t)=t^{2} +2t-4$

Now,

When function p(t) = 11 , t will be

$p(t)=t^{2} +2t-4$

11 = t²+2t-4

0 = t² + 2t - 15

t² +2t-15 = 0

t² +(5-3)t-15 = 0

t² +5t-3t-15 = 0

t(t+5)-3(t+5) = 0

(t-3)(t+5) = 0

t = 3 , -5

as t cannot be -ve as given ( t≥0)

so,

t = 3

Now,

the velocity when p(t)=11

As we know velocity = $\frac{position}{time}$

therefore to get the value of velocity from function p(t)

we have to differentiate the function with respect to time

$\frac{d(p(t))}{dt} =\frac{d}{dt} (t^{2} +2t-4)$

v(t) = 2t + 2

where v(t) = velocity at that time

as t = 3 for p(t)=11

so ,

v(t) = 2t + 2

v(t) = 2*3 + 2

v(t) = 8

Hence, the velocity when function p(t)=11 is 8 .

To know more about function here:

brainly.com/question/12431044

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4 0

2 years ago