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3 years ago

If the cross-sectional area of a wire is decreased while all other factors remain the same, how will the resistance change?

Physics

1 answer:

Nataly [62]3 years ago

4 0

Answer:

A. It will increase

Explanation:

Area of a wire is:

R = ρL/A

where ρ is the resistivity of the wire,

L is the length of the wire,

and A is the cross-sectional area.

If A decreases, while ρ and L stay the same, then R will increase.

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Five basket ball teams are playing in a tournament. The teams will play with each other only one time. How many games will be pl

77julia77 [94]

Ten games will be played.

The first team can be any one of 5 . For each of those, the opponent can be any one of the other 4 .

Number of ways to pair them up = (5 x 4) = 20 ways .

BUT ... Whether the Reds play the Blues, or the Blues play the Reds, it's the SAME GAME. Each possible game shows up twice in the list of 20 ways. So there are really only 10 different pairs ==> 10 games .

3 0

3 years ago

What is the speed of an object traveling a distance of 25 meters in 25 seconds

sergeinik [125]

Answer:

1 meter per second

Explanation:

Speed=Distance/Time

S=D/T

S=25/25

S=1

6 0

3 years ago

Read 2 more answers

Which element is found in group 17 and period 2

exis [7]

The answer is fluorine

4 0

3 years ago

Sunburn is caused by ultraviolet light waves having a frequency of around 10^16 Hz. What is their wavelength if the speed of lig

Taya2010 [7]

$Given:\\f=10^{16}Hz\\c=3\cdot 10^8\frac{m}{s} \\\\Find:\\\lambda =?\\\\Solution:\\\\\lambda = \frac{c}{f} \\\\\lambda= \frac{3\cdot 10^8\frac{m}{s}}{10^{16}Hz} =3\cdot 10^{-8}m = 30nm$

5 0

3 years ago

A boat heads directly across a river. Its speed relative to the water is 3 m/s. It takes it 539 seconds to cross, but it ends up

nikklg [1K]

Answer:

3.24 m/s

Explanation:

Suppose that the boat sails with velocity (relative to water) direction being perpendicular to water stream. Had there been no water flow, it would have ended up 0m downstream

Therefore, the river speed is the one that push the boat 662 m downstream within 539 seconds. We can use this to calculate its magnitude

$v_r = 662 / 539 = 1.23 m/s$

So the boat velocity vector relative to the bank is the sum of of the boat velocity vector relative to the water and the water velocity vector relative to the bank. Since these 2 component vectors are perpendicular to each other, the magnitude of the total vector can be calculated using Pythagorean formula:

$v = \sqrt{v_b^2 + v_r^2} = \sqrt{3^2 + 1.23^2} = \sqrt{9 + 1.5129} = \sqrt{10.5129} = 3.24$ m/s

5 0

4 years ago