If the cross-sectional area of a wire is decreased while all other factors remain the same, how will the resistance change?
1 answer:
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Answer:
x = 76.5 m
Explanation:
Let's use Newton's second law at the point of contact between the wheel and the floor.
fr = m a
fr = miy N
N-W = 0
N = W
μ mg = m a
a = miu g
a = 0.600 9.8
a = 5.88 m / s²
Having the acceleration we can use the kinematic relationships to find the distance
² = v₀² + 2 a x
= 0
x = -v₀² / 2 a
Acceleration opposes the movement by which negative
x = - 30²/2 (-5.88)
x = 76.5 m
Answer:
a
b
Explanation:
From the question we are told that
The diameter of the Ferris wheel is
The period of the Ferris wheel is
The mass of the passenger is
The apparent weight of the passenger at the lowest point is mathematically represented as
Where is the centripetal force on the passenger, which is mathematically represented as
Where is the angular velocity which is mathematically represented as
substituting values
and r is the radius which is evaluated as
substituting values
So
W is the weight which is mathematically represented as
So
The apparent weight of the passenger at the highest point is mathematically represented as
substituting values