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sergeinik [125]
3 years ago
10

True or false? Scientific theories lack experimental support

Physics
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

Hey there!

It is false. Theories can be repeatedly tested to give people an explanation of the world.

Let  me know if this helps :)

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A chef places an open sack of flour on a kitchen scale. The scale reading of
Novay_Z [31]

Answer:

Explanation:

Given

Initial reading on scale =40 N

So, we can conclude that weight of the sack is 40 N

After this a 10 N force is applied upward on the sack such that the net force becomes (40-10) N downward (because downward force is more)

This net downward force is the resultant of earth graviational pull and the applied upward force.

So, this downward force acts on the machine which inturn applies an upaward force of same magnitude called Normal reaction.

This situation can be diagramatically represented by figure given below  

4 0
3 years ago
Forces can act on an object in the same direction or in opposite. how does each situation affect the motion of the object?
Anon25 [30]



Hi pupil here's your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



Action and Reaction do not act on the same body !! If they acted on the same body, the resultant force will be zero and their could be never accelerated motion.

If both the forces acted on the same body, then if they are equal to opposite direction the object will remain stationary. If on of the forces is greater than other the object will move in the direction of greater force.

If both acted in the same direction there would be an accelrated motion.




⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅





Hope this helps . . . . .
5 0
3 years ago
Select all that apply.
slega [8]
A chemist is likely to:
<span>1. analyze the ingredients in ice cream
</span><span>2. determine how to separate gasoline from other substances in petroleum</span>
7 0
3 years ago
Read 2 more answers
A block is resting on a platform that is rotating at an angular speed of 2.4 rad/s. The coefficient of static friction between t
Sloan [31]

Answer:

r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.

Explanation:

From a sum of forces:

Ff = m*a   where Ff = μ * N    and a = \frac{V^2}{r}=\omega^2*r

N - m*g = 0   So, N = m*g.   Replacing everything on the original equation:

\mu*m*g = m*\omega^2*r   (eq2)

Solving for r:

r = \frac{\mu*g}{\omega^2}=1.41m

If we analyze eq2 you can conclude that as r grows, the friction has to grow (assuming that ω is constant), so the smallest distance would be 0 and the greatest 1.41m. Beyond that distance, μ has to be greater than 0.83.

4 0
3 years ago
How are the amplitude and energy of a wave related
In-s [12.5K]
I would go with the last two because they are the same  please give me brainiest if i am right

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3 0
3 years ago
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