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3 years ago

As the velocity of the sound source approaches the speed of sound, the wave fronts ahead of the object begin to appear as:

Physics

1 answer:

sineoko [7]3 years ago

4 0

Answer:

The correct answer is D

shock waves

Explanation:

When a body approaches the speed of sound in the media, the waves it emits are getting closer and closer to each other, the envelope (sum) results in a kind of cylindrical cone that is similar to that formed in a supersonic process

The correct answer is D

When the speed of sound is exceeded, the body goes faster than the wave, so the so-called shock waves are formed.

They carry a lot of energy

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72.0-kg person pushes on a small doorknob with a force of 5.00 N perpendicular to the surface of the door. The doorknob is locat

expeople1 [14]

Answer: $I=2 kg-m^2$

Explanation:

Given

mass $m=72 kg$

Force $F=5 N$

door knob is located at a distance of r=0.8 m from axis

Angular acceleration of door $\alpha =2 rad/s^2$

Torque $T=I\alpha =F\times r$

where I=moment of inertia

$5\times 0.8=I\times 2$

$I=2 kg-m^2$

4 0

3 years ago

A coil of wire with 100. circular turns of radius 8.00 cm is in a uniform magnetic field along the axis of the coil. The resista

andreyandreev [35.5K]

I think Im gonna have to go with C 6.00 T/s but Im not sure

6 0

3 years ago

The resistance, R, of a wire varies directly as its length and inversely as the square of its diameter. If the resistance of a w

lbvjy [14]

R is proportional to the length of the wire:

R ∝ length

R is also proportional to the inverse square of the diameter:

R ∝ 1/diameter²

The resistance of a wire 2700ft long with a diameter of 0.26in is 9850Ω. Now let's change the shape of the wire, adding and subtracting material as we go along, such that the wire is now 2800ft and has a diameter of 0.1in.

Calculate the scale factor due to the changed length:

k₁ = 2800/2700 = 1.037

Scale factor due to changed diameter:

k₂ = 1/(0.1/0.26)² = 6.76

Multiply the original resistance by these factors to get the new resistance:

R = R₀k₁k₂

R₀ = 9850Ω, k₁ = 1.037, k₂ = 6.76

R = 9850(1.037)(6.76)

R = 69049.682Ω

Round to the nearest hundredth:

R = 69049.68Ω

8 0

3 years ago

Convert 0.700 atm of pressure to its equivalent in millimeters of mercury.

inna [77]

Answer:

532 millimeters of mercury

Explanation:

In order to convert the pressure from atm to millimeters of mercury (mm Hg), we should remind the conversion factor between the two units:

1 atm = 760 mm Hg

Therefore, we can solve the problem by setting up the following proportion:

$1 atm : 760 mmHg = 0.700 atm : x$

Solving for x, we find

$x=\frac{(760 mmHg)(0.700 atm)}{1 atm}=532 mmHg$

5 0

3 years ago

PLEAS HELP.

koban [17]

A: put an atom on a poster in the exhibit
 Good luck. The poster itself is made of trillions of trillions of trillions
 of atoms. You could not see the extra one any easier than you could
 see the ones that are already there, and even if you could, it would be
 lost in the crowd.

B: use a life size drawing of an atom
 Good luck. Nobody has ever seen an atom. Atoms are too small
 to see. That's a big part of the reason that nobody knew they exist
 until less than 200 years ago.

D: set up a microscope so that visitors can view atoms
 Good luck. Atoms are way too small to see with a microscope.

C: Display a large three dimensional model of an atom.
 Finally ! A suggestion that makes sense.
 If something is too big or too small to see, show a model of it
 that's just the right size to see.

8 0

3 years ago