Answer:
a= 17.69 m/s^2
Explanation:
Step one:
given data
A car accelerates uniformly from rest to 23 m/s
u= 0m/s
v= 23m/s
distance= 30m
Step two:
We know that
acceleration= velocity/time
also,
velocity= distance/time
23= 30/t
t= 30/23
t= 1.30 seconds
hence
acceleration= 23/1.30
accelaration= 17.69 m/s^2
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Answer:
a) Fg = 9.495x10⁻⁶N
b) Fg = 3.908x10⁻⁶N
c)

Explanation:
Given:
m₁ = mass = 3x10⁴kg
r = radius = 1 m
m₂ = 9.3 kg
Questions:
a) What is the magnitude of the gravitational force due to the sphere located at R = 1.4 m, Fg = ?
b) What is the magnitude of the gravitational force due to the sphere located at R= 0.21 m, Fg = ?
c) Write a general expression for the magnitude of the gravitational force on the particle at a distance r ≤ 1.0 m from the center of the sphere.
a) Since R > r, the equation for the gravitational force is:

Here,
G = gravitational constant = 6.67x10⁻¹¹m³/s² kg
Substituting values:

b) Since R < r, the equation for the gravitational force is:

c) The general expression for the magnitude of the gravitational force on the particle at a distance r ≤ 1.0 is the same to b)

Speed<span> has the dimensions of distance divided by time. The </span>SI unit<span> of </span>speed<span> is the metre per second, but the most common </span>unit<span> of </span>speed<span> in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour.</span>
To solve this problem it is necessary to apply the concepts related to diffraction through a circular opening.
By definition the angular resolution is given by

Where,

D = Diameter of the lens aperture.
Our values are given as,


Therefore replacing,


Therefore the angular separation is 