Electrons fill the electron orbitals (s, p, d, or f) starting from the lowest energy level going to the highest energy level.
I hope this helps. let me know if you need more information such as what the
In cell biology, the cytoplasm is the material or protoplasm within a living cell, excluding the cell nucleus. It comprises cytosol (the gel-like substance enclosed within the cell membrane) and the organelles – the cell's internal sub-structures. All of the contents of the cells of prokaryote organisms (such as bacteria, which lack a cell nucleus) are contained within the cytoplasm. Within the cells of eukaryote organisms the contents of the cell nucleus are separated from the cytoplasm, and are then called thenucleoplasm. The cytoplasm is about 80% water and usually colorless.[1]
It is within the cytoplasm that most cellular activities occur, such as many metabolic pathways including glycolysis, and processes such as cell division. The concentrated inner area is called the endoplasm and the outer layer is called the cell cortex or theectoplasm.
Movement of calcium ions in and out of the cytoplasm is a signaling activity for metabolic processes.[2]
In plants, movement of the cytoplasm around vacuoles is known as cytoplasmic streaming.
The noble gases are relatively unreactive because they have a stable octet of valence electrons.
Thus, they do not tend to undergo reactions in which they will gain or lose valence electrons,
However, <em>only He, Ne, and Ar are inert</em>. Kr and Xe combine with other highly reactive elements to form stable compounds.
To find the molecular formula from the empirical formula, you need to find a multiple (x) that will give you the molar mass of the compound which in the question is 54 g/mol.
If C₂H₃ is the empirical formula
molar mass of empirical formula = (12 × 2) + (1 × 3) g/mol
= 27 g/mol
let x = multiple
let molecular formula = C₂ₓ H₃ₓ
multiple = molecular mass ÷ empirical mass
= 54 g/mol ÷ 27 g/mol
= 2
If molecular formula = C₂ₓ H₃ₓ
then molecular formula = C₂₍₂₎H₃₍₂₎
= <span>C₄H</span>₆