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Paladinen [302]
3 years ago
7

Fine-grainted igneous rocks form?

Chemistry
1 answer:
Harman [31]3 years ago
5 0
In molten lava like all the rest.

Hope it helped!!!
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You are on a field trip to a nearby lake for biology class and want to perform a quick analysis of the water’s approximate pH le
vitfil [10]
The easiest way to approximate ph level is through the ph paper measurement system because using pH paper would be best for doing a quick measurement in the field. It does not essentially need to be calibrated or standardized and the papers make available an instant estimate.
8 0
3 years ago
What is the molarity of a solution that contains 9.63 grams of HCl in 1.5 liters of solution? 1 H 1.01 Hydrogen 17 Cl 35.45 Chlo
madam [21]
Hey there !

Molar mass HCl :

HCl =1.01 + 35.45 => 36.46 g/mol

Number of moles ( solute) :

n = m / mm

n = 9.63 / 36.46

n = 0.2641 moles

Therefore :

M = moles / volume ( L )

M = 0.2641 / 1.5

=> 0.176 M


7 0
4 years ago
SnO2 + C → Sn + СО balance​
rewona [7]

Answer:

Tin(IV) Oxide + Carbon = Tin + Carbon Monoxide

Explanation:

7 0
3 years ago
Read 2 more answers
Sterling silver contains silver and copper metals. if a sterling silver chain contains 17.6g of silver and 2.40g of copper, what
Bogdan [553]

Answer:-  0.88

Solution:- Masses of silver and copper metals are given and we are asked to calculate the percentage of silver in the alloy.

mass percent of Ag = (\frac{mass of Ag}{mass of alloy})*100

Mass of Ag = 17.6 g

mass of Cu = 2.40 g

mass of alloy = 17.6 g + 2.40 g = 20.0 g

Let's plug in the values in the formula:

mass percentage of Ag = (\frac{17.6}{20.0})*100

mass percentage of Ag = 88%

So, the mass percentage of silver in sterling silver is 88% and in decimal form it is 0.88.

7 0
3 years ago
If i have 340mL of a 1.5 M NaBr solution, What will the concentration be for 1000mL?
Gekata [30.6K]

Answer:

0.51M

Explanation:

Given parameters:

Initial volume of NaBr = 340mL

Initial molarity  = 1.5M

Final volume  = 1000mL

Unknown:

Final molarity = ?

Solution;

This is a dilution problem whereas the concentration of a compound changes from one to another.

In this kind of problem, we must establish that the number of moles still remains the same.

    number of moles initially before diluting = number of moles after dilution

Number of moles  = Molarity x volume

Let us find the number of moles;

          Number of moles  = initial volume x initial molarity

Convert mL to dm³;

                  1000mL  = 1dm³

                     340mL gives \frac{340}{1000}   = 0.34dm³

Number of moles  = initial volume x initial molarity  = 0.34 x 1.5 = 0.51moles

Now to find the new molarity/concentration;

               Final molarity  = \frac{number of moles}{Volume}    = \frac{0.51}{1}    = 0.51M

We can see a massive drop in molarity this is due to dilution of the initial concentration.

6 0
4 years ago
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