Answer:
The speed at which she threw the marshmallow is approximately 4.76 m/s
Explanation:
The given in formation are;
The range in which the marshmallow was thrown = 2 m (The location of her friend)
The angle at which the marshmallow was thrown = 30 degrees
The horizontal range is given by the following formula;
Where;
R = The range = 3 m
u = The initial velocity
θ = The angle at which the marshmallow was thrown = 30°
g = The acceleration due to gravity = 9.81 m/s²
By substitution, we have;
u ≈ √(22.66) ≈ 4.76 m/s
u ≈ 4.76 m/s
The speed at which she threw the marshmallow ≈ 4.76 m/s.