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nexus9112 [7]
3 years ago
15

How many moles of aluminum hydroxide would be produced from 4.6 miles of calcium hydroxide

Chemistry
1 answer:
Lorico [155]3 years ago
8 0
<h3>Answer:</h3>

3.067 moles

<h3>Explanation:</h3>
  • Assuming the reaction in question is between Aluminium chloride and calcium hydroxide to produce calcium chloride and aluminium hydroxide, then we can answer the question.
  • The equation for the reaction is given by;

2AlCl₃ + 3Ca(OH)₂ → 2Al(OH)₃ + 3CaCl₂

We are given;

  • 4.6 moles of Calcium hydroxide

We are required to determine the number of moles of Aluminium hydroxide formed.

From the equation, 3 moles of Ca(OH)₂ reacts to produce 2 moles of Al(OH)₃

Therefore;

Moles of Al(OH)₃ = Moles of Ca(OH)₂ × 2/3

                            = 4.6 moles × 2/3

                            = 3.067 moles

Therefore, 3.067 moles of Al(OH)₃ would be produced.

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1 mol of any particles has 6.02 * 10 ²³ particles.

If we look at 1 NH3 (1 mol NH3 or 1 molecule NH3), we can see that 1 molecule NH3 has 1 atom of N and 3 atoms of H; also 1 mole of NH3 has 1 mole of N atoms and 3 moles of H atoms.

So, 1 mol of NH3 has 1 mol of N atoms,
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2.79 mol of N atoms* 6.02 * 10 ²³ N atoms/ 1 mol N atoms = 1.68*10²⁴ N-atoms 

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Explanation :

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Now we have to calculate the value of K for the final reaction.

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If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

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