Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal
1 answer:
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Answer:
A. 96.3 mg/dL
Absolute error: 5.7 mg/dL
Relative error: 5.6%
B. 97.2 mg/dL
Absolute error: 4.8 mg/dL
Relative error: 4.7%
C. 104.8 mg/dL
Absolute error: 2.8 mg/dL
Relative error: 2.7%
D. 111.5 mg/dL
Absolute error: 9.5 mg/dL
Relative error: 9.3%
E. 110.5 mg/dL
Absolute error: 8.5 mg/dL
Relative error: 8.3%
Explanation:
The formula for the absolute error is:
Absolute error = |Actual Value - Measured Value|
The formula for the relative error is:
Relative error = |Absolute error/Actual value|
In your exercise, we have that
Actual Value = 102.0 mg/dL
A. 96.3 mg/dL:
B. 97.2 mg/dL
C. 104.8 mg/dL
D. 111.5 mg/dL
E. 110.5 mg/dL
The graphics in the attachment is part of the question, which was incomplete.
Answer: Fr = 102N and angle of approximately 11°.
Explanation: From the attachment, it is observed that from the three forces acting on M, two are perpendicular. So to find them, we have to show their x- and y- axis components. From the graph:
Fx = 70+40-10 = 100
Fy = 40-20 = 20
Now, as the forces form a triangle, the totalforce is:
Fr =
Fr =
Fr = ≈ 102N
To determine the angle requested, we use:
arctg H =
arctg H =
H = tg 0.2 ≈ 11°.
