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love history [14]
3 years ago
5

Below are 5 sets of potential solutes for you to compare. Both members of each pair are very soluble in water. If you had equal

molar concentrations of each solution, which member of each pair would theoretically be the better conductor of electricity?
1. CsCl or CaCl 2
2. CaS or Li 2 S
3. KBr or AlCl 3
4. AlCl 3 or MgC 2
5. KI or K 2 S
Chemistry
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:

CaCl2, Li2S, AlCl3, AlCl3, K2S

Explanation:

When figuring out which is a better conductor of electricity you want to look at which has the largest yield of dissociated ions.

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Which of the following would happen if Earth's moon were half the size that it is now? O The oceans' tidal variations would be s
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What best discribes the relationship between wavelength and frequency in a electromagnetic wave
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Answer:

The higher the frequency, the shorter the wavelength

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3 years ago
A bottle containing 415 g of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific grav
neonofarm [45]

Answer: 483 mL of the cleaning solution are used to clean hospital equipment

Explanation:

The question requires us to calculate the volume, in mL, of solution is used to clean hospital equipment, given that 415g of this solution are used and the specific gravity of the solution is 0.860.

Measurements > Density

Specific gravity is defined as the ratio between the density of a given substance to the density of a reference material, such as water:

Specific\text{ gravity = }\frac{density\text{ of substance}}{density\text{ of reference substance}}

The density of a substance is defined as the ratio between the mass and the volume of this substance:

density=\frac{mass}{volume}

Considering the reference substance as water and its density as 1.00 g/mL, we can determine the density of the substance which specific gravity is 0.860:

0.860=\frac{density\text{ of substance}}{1.00g/mL}\rightarrow density\text{ of substance = 0.860g/mL}

Thus, taking water as the reference substance, we can say that the density of the cleaning solution is 0.860 g/mL.

Now that we know the density of the cleaning solution (0.860 g/mL) and the mass of solution that is used to clean hospital equipment (415g), we can calculate the volume of solution that is used to clean the equipment:

\begin{gathered} density=\frac{mass}{volume}\rightarrow volume=\frac{mass}{density} \\  \\ volume=\frac{415g}{0.860g/mL}=483mL \end{gathered}

Therefore, 483 mL of the cleaning solution are used to clean hospital equipment.

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1 year ago
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Answer:

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Explanation:

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3 years ago
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