If the current takes him downstream we must find the resultant vector of the velocities:

Then if the river is 3000 m-wide the swimmer will have to pass:
1.3520747 · 300 = 4056.14 m t = 4056.14 m : 1 m/s
a ) It takes
4056.15 seconds ( 1 hour 7 minutes and 36 seconds ) to cross the river.
b ) 0.91 · 3000 =
2730 mHe will be 2730 m downstream.
V = IR
I = V/R
I = 12/6
I = 2 amps
Answer:
0.012-m
Explanation:
∆L = α × Lo × (T-To)
α is the coefficient of linear expansion = 12 × 10-6 K-1
Lo = Initial length = 25-m
∆L = Change in length
(T-To) = 40 K
∆L = 12 × 10-6 × 25 × 40
∆L = 0.012-m
Answer:
2.24 m/s
Explanation:
resolving force of 29.2 N in x component
Fx = 29.2 cos 57.7
Fx = 15.6N
as force of friction is 12.7 N hence net force which produces acceleration is
15.6-12.7=2.9 N
by Newton 's law a=f/m
a= 2.9/6.87=0.422 m/s^2
now equation of motion is
v^2= U^2+2as
= 0^2+2(.422)(5.93)
v^2=5.00
v=2.24 m/s