When in the melting process particles start to move more freely when in the freezing process particles tend to slow and vibrate in place
Answer:
2.87m
Explanation:
Using the law of gravitation to solve this question
F = GMm/r²
G is the gravitational constant
M and m are the masses
r is the distance between the masses
Substitute the given values
G = 6.67×10^-11 m³/kgs²
M =8.8 x 10^6 kg
m = 5.6 x 10^5 kg
F =440N
400 = 6.67×10^-11×8.8 x 10^6 ×5.6 x 10^5/r²
400r² = 328.698×10
400r² = 3286.98
r² = 3286.98/400
r² = 8.21745
r = √8.21745
r = 2.87m
Hence the distance of separation is 2.87m
question: Please help!!!
If a bottle is being squeezed with a force of 10 Newtons and the area of the bottle is 15
squared inches. What is the pressure??
Answer:
1025.64 N/m²
Explanation:
Pressure: This can be defined as the ratio of force to area. The si unit of pressure is N/m².
From the question,
P = F/A........................ Equation 1
Where F = Force, A = Area.
Given: F = 10 Newtons, A = 15 Squared Inches = (15×0.00065) = 0.00975 m²
Substitute these values into equation 1
P = 10/0.00975
P = 1025.64 N/m²
Hence the pressure of the bottle is 1025.64 N/m²
Answer:
Explanation:
We know,
..............(1)
where,
η = Efficiency of the engine
T₁ = Initial Temperature
T₂ = Final Temperature
Q₁ = Heat available initially
Q₂ = Heat after reaching the temperature T₂
Given:
η =0.280
T₁ = 3.50×10² °C = 350°C = 350+273 = 623K
Q₁ = 3.78 × 10³ J
Substituting the values in the equation (1) we get
or
or
⇒ 
Now,
The entropy change (
) is given as:
or
substituting the values in the above equation we get
