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diamong [38]
3 years ago
7

An electric kettle. The input energy is 10 Joules. The useful output energy is heat 9

Physics
1 answer:
mina [271]3 years ago
3 0

Answer:

Efficiency = 90 %

Wasted energy = 10 %

Explanation:

Since we have the input energy and useful output energy of the electric kettle, the only thing we are required to calculate here is its efficiency. This is gotten from

E = useful output energy/input energy × 100

E = 9/10 × 100 = 90 %

The percentage of wasted energy is

W = wasted energy/input energy × 100

W = 1/10 × 100

W = 10 %

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