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Katyanochek1 [597]
3 years ago
10

a kid jumping on a trampoline reaches a height of 0.925m. what was his speed when he left the trampoline?

Physics
1 answer:
Paha777 [63]3 years ago
3 0
As the kid rises to a height of 0.925 meters, his velocity decreases at the rate of 9.8 m/s each second. At the maximum height, his velocity is 0 m/s. Use the following equation to solve this problem.

vf^2 = vi^2 + 2 * a * d, vf = 0, a = -9.8
0 = vi^2 + 2 * -9.8 * 0.925
vi = √18.13
This is approximately 4.26 m/s.

I hope this helps, have a great day, and God bless.
Brainliest is always appreciated :)
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v=18.89\frac{m}{s}

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)

Solving N from (2) and replacing in (1):

N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c

The centripetal acceleration is given by:

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Replacing and solving for v:

gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}

4 0
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What is the time it takes an object that moves at 25 m/min to travel 505 meters?
Mrac [35]

Answer:

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Answer:

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Explanation:

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Number of turns in primary N_p=2250

For transformer we know that \frac{V_p}{V_s}=\frac{N_p}{N_s}

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Answer:

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#1

W= mg

W= 54 x 1.6

W=86.4 N

#2

W=mg

W= 66 x 1.6

W= 105.6 N

8 0
2 years ago
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