Answer:
The active ingredients in baking soda (NaHCO3) are
and 
when Baking soda reacts with Acetic acid
Molecular equation
NaHCO3(aq) + CH3COOH(aq) → Na(CH3COO)(aq) + CO2(g) +H2O(l)
Ionic equation
→ 
as is present on both sides so it will cancel out and the net ionic equation will be
→ 
Sodium chloride is an ionic compound. ionic compound is when the compound itself is made up of a metal and non-metal element.
thus the answer is potassium bromide and cesium chloride.
1 mole consist of 6.022 ×10 ²³
Therefore in NaOH = 6.022 ×10 ²³ moles of NaOH
B. 3.0 mol·L⁻¹ NaCl
Explanation:
Freezing point is a colligative property: it depends only on the number of particles in solution.
The for freezing point depression ΔT_f is
ΔT_f = iK_fb
where
i = the number of moles of particles available from one mole of solute
K_f = the molal freezing point depression constant
b = the molal concentration of the solute
All your solutions are aqueous NaCl. They differ only in their concentrations.
Thus, the most concentrated solution will have the greatest freezing point depression and the lowest freezing point.
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For #1 the answer is dependent relationship . 2. answer is independent relationship . the last question the answer is dependent.
