Q2 is 1.60x10^-19.
because if you round up or add, you will come with q2
Answer:
15.3 sorry if i got it wrong
Explanation:
Answer:
the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Explanation:
For this exercise we can calculate the initial and final mechanical energy
Em₀ = U = m g y₁
= U = m g y₂
we look for the variation of the energy
ΔEm = Em_{f} - Em₀
ΔEm = m g (y_{f} -y₀)
ΔEm = m g (0.86 -1.2)
ΔEm = -3.332 m
We can see that there is a decrease in mechanical energy, this is transformed into internal energy of the ball during the impact with the ground, this energy can be formed by several factors such as a part of the friction with the surface, an increase in body temperature or a deformation of the body; there may be a contribution from several of these factors.
In conclusion the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Answer:
Explanation:
GIVEN DATA:
<u><em>Solution:</em></u>
the velocity for centre of the mass
input the values into the formula.
open the bracket
collect like terms
total momentum
Answer:
= - 26.31 kJ
Explanation:
we know that number of moles is calculated as
= 0.00476 mol
Heat absorbed by calorimeter
= 26.87 kJ
Enthalpy of combustion
= - 55290.12 kJ/mol
Negative sign shows that the heat is released
The balanced reaction
ΔHc = ΔU + Δng (RT)
-55290.12 = ΔU + (12 - 12) *(RT)
= - 26.31 kJ