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skad [1K]
3 years ago
14

The work of a student to solve a set of equations is shown:

Mathematics
2 answers:
lesantik [10]3 years ago
5 0

<span>If you would like to know in which step did the student first make an error, you can find this using the following steps:

y = 4 - 2z
4y = 2 - 4z
________________
-4(y) = -4(4 - 2z)
</span>4y = 2 - 4z<span>
________________
-4y = -16 + 8z ... Step 2
</span><span>4y = 2 - 4z</span><span>
________________
0 = -16 + 8z + 2 - 4z</span>

<span>16 - 2 = 4z</span>

<span>14 = 4z</span>

<span>z = 14/4 = 7/2</span>

<span>
The correct result would be: Student made an error in Step 2.</span>

KATRIN_1 [288]3 years ago
3 0

Answer:

Step 2

Step-by-step explanation:

y = 4 - 2z

4y = 2 - 4z

________________

-4(y) = -4(4 - 2z)

4y = 2 - 4z

________________

-4y = -16 + 8z ... Step 2

4y = 2 - 4z

________________

0 = -16 + 8z + 2 - 4z

16 - 2 = 4z

14 = 4z

z = 14/4 = 7/2

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Step-by-step explanation:

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3 years ago
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neonofarm [45]

The sum of the expression (–x² + x) and (x² – 3x – 1) will be –2x – 1. Then the correct option is D.

<h3>What is Algebra?</h3>

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

The expression can be written as

(–x² + x) and (x² – 3x – 1)

Then the sum of the expression (–x² + x) and (x² – 3x – 1) will be

(–x² + x) + (x² – 3x – 1) = –2x – 1

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3 years ago
Rearrange the equation so a is the independent variable.<br><br> 3a-7= -4b+1<br><br> Please help! :)
Aleksandr-060686 [28]

Answer:

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3 years ago
ANSWER QUICKLY!!!!!
Paul [167]

Answer:

1. The possible roots are ±1, ±2, ±3, ±6. These are the factors of the trailing constant (6) divided by the factors of the leading coefficient (1). When the leading coefficient is 1, the possible roots are the factors of the constant

2. The polynomial is easier to evaluate when it is written in Horner form:

 f(x) = ((x -4)x +1)x +6

To show that 2 is a zero, we want to find f(2):

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3.  Using synthetic division (attached) or polynomial long division, we can divide the given polynomial by (x-2) to find the remaining factors. This division gives (x^2 -2x -3), which can be factored as (x -3)(x +1), so the three actual roots are ...

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4. In factored form, the polynomial can be written ...

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The first factor was found from the fact that 2 was given as a zero of the function. For any zero "a", a factor of the polynomial is (x-a).

The remaining factors were found by factoring the quadratic trinomial that resulted from the division of f(x) by x-2. That trinomial is x^2 -2x -3.

There are a number of methods that can be used to factor x^2 -2x -3. Again, the rational root theorem can help. It suggests that ±1 and ±3 are possible roots.

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2 years ago
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