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skad [1K]
4 years ago
14

The work of a student to solve a set of equations is shown:

Mathematics
2 answers:
lesantik [10]4 years ago
5 0

<span>If you would like to know in which step did the student first make an error, you can find this using the following steps:

y = 4 - 2z
4y = 2 - 4z
________________
-4(y) = -4(4 - 2z)
</span>4y = 2 - 4z<span>
________________
-4y = -16 + 8z ... Step 2
</span><span>4y = 2 - 4z</span><span>
________________
0 = -16 + 8z + 2 - 4z</span>

<span>16 - 2 = 4z</span>

<span>14 = 4z</span>

<span>z = 14/4 = 7/2</span>

<span>
The correct result would be: Student made an error in Step 2.</span>

KATRIN_1 [288]4 years ago
3 0

Answer:

Step 2

Step-by-step explanation:

y = 4 - 2z

4y = 2 - 4z

________________

-4(y) = -4(4 - 2z)

4y = 2 - 4z

________________

-4y = -16 + 8z ... Step 2

4y = 2 - 4z

________________

0 = -16 + 8z + 2 - 4z

16 - 2 = 4z

14 = 4z

z = 14/4 = 7/2

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A combined total of $46,000 is invested in two bonds that pay 4% and
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Answer: 4%-16000 and 9.5%-30000

Why:

1) x+y=46000

x=46000-y

2) 4%x+9,5%y=3490;

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5 0
3 years ago
Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.
chubhunter [2.5K]

The value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

<h3>How to evaluate the expression?</h3>

The expression is given as:

3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two

Rewrite properly as:

[3² * 3⁻⁵]/[5⁻²]

Apply the negative exponent law of indices

So, we have

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]

Apply the exponent law of indices

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]

This gives

[3² * 3⁻⁵]/[5⁻²] = 25/27

Hence, the value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

Read more about expressions at:

brainly.com/question/723406

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