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son4ous [18]
3 years ago
11

Question 2 (5 points)

Physics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

Frequency of sound wave = 198.83 hertz (Approx.)

Explanation:

Given:

Velocity of sound wave in air = 340 m/s

Wavelength = 1.71 meter

Find:

Frequency of sound wave

Computation:

Frequency = Velocity / Wavelength

Frequency of sound wave = Velocity of sound wave in air / Wavelength

Frequency of sound wave = 340 / 1.71

Frequency of sound wave = 198.8304

Frequency of sound wave = 198.83 hertz (Approx.)

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Forehead, Feet and Elbows, if the person is perfect health condition.
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3 years ago
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A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound
Strike441 [17]

Answer:

5.997m/s

Explanation:

We were told to calculate the speed of the ball,

Given speed of sound as 340 m

And we know that the sound of the ball hitting the pins is at 2.80 s after the ball is released from his hands.

Speed of ball = distance traveled/(time of hearing - time the sound travels).

Speed= S/t

Where S= distance traveled

t= time of hearing - time the sound travels

time=time for ball to roll+timefor sound to come back.

time of sound=16.5/340

=0.048529secs

solving for speedof ball

Then,Speed of ball = distance traveled/(time of hearing - time the sound travels).

=16.5/(2.80-0.048529) m/s = 5.997m/s

Therefore, the speed of the ball is

5.997m/s

4 0
3 years ago
A ball with a weight of 2 N is attached to the end of a cord of length 2m . The ball is whirl in a vertical circle counterclockw
ZanzabumX [31]

Answer:

we agree with

Edgar: The net force on the ball at the top position is 9 N. Both the tension and the weight are acting downward so you have to add them.

Explanation:

Weight of the ball is given as

W = 2N

so we have

m = \frac{W}{g}

m = 0.204 kg

now tension force at the top is given as

T_{top} = 7 N

T_{bottom} = 15 N

Now at the top position by force equation we can say that ball will have two downwards forces

1) Tension force

2) Weight of the ball

so net force on the ball is given as

F_{net} = T + W

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So we agree with

Edgar: The net force on the ball at the top position is 9 N. Both the tension and the weight are acting downward so you have to add them.

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Answer:

15 miles

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6 miles per hour

2 1/2 hours

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A point on the string of a violin moves up and down in simple harmonic motion with an amplitude of 1.24 mm and frequency of 875
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Using

V = Amplitude x angular frequency(omega)

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B. .Acceleration is omega² x radius= 104ms²

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