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3 years ago

5

The watering can that Carlos uses in his vegetable garden holds 5 of a certain unit of liquid volume. When full, how much water

is in the watering can?

1 answer:

Kazeer [188]3 years ago

4 0

An average watering can is 5 liters so 5 liters

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Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

4 years ago

What is the length of (AB)?

earnstyle [38]

AB = 4 units
BC = 8 units
perimeter = 2(l+b) = 2(8+4) = 2(12) = 24 units

hope it helps...!!!

3 0

2 years ago

Read 2 more answers

Plsss help me! Brainlist!!

dangina [55]

Answer: = (the third option)

Step-by-step explanation

4 0

3 years ago

Read 2 more answers

NEED ANSWERS ASAP

Ray Of Light [21]

If it's most likely A. or B.

Correct me if I'm wrong.

But, I hope this helps!

5 0

3 years ago

Read 2 more answers

At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs

rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - $^9C_1=9$

Number of ways for second place - $^8C_1=8$

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - $^8C_1=8$

Number of ways for second place - $^7C_1=7$

Total number of different tickets are possible is

$n=9\times 8\times 8\times 7$

$n=4032$

Therefore, 4032 different tickets are possible.

8 0

3 years ago