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Novosadov [1.4K]
3 years ago
13

2000-kg car decelerated from 10 m/s to 5 m/s. What is the work done on the car ?

Physics
1 answer:
sergey [27]3 years ago
3 0
A 2000-kg car decelerated from 10 m/s to 5 m/s. What is the work done on the car ?

Known :

Car’s mass (m) = 2000 kg

Initial speed (vo) = 10 m/s

Final speed (vt) = 5 m/s

Wanted: net work

Solution :

Net work :

Wnet= ΔEK

Wnet = ½ m (vt2 – vo2)

Wnet = ½ (2000)(52 – 102)

Wnet = (1000)(25 – 100)

Wnet = (1000)(-75)

Wnet = -75,000 Joule

The minus sign indicates that the direction of displacement is opposite with the direction of the net force.
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The wavelength was doubled, and its energy will be increased by 4 times.

looking at the formula

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hence it is clear from above that energy is directly proportional to the square of the wavelength.

hence, The wavelength was doubled, and its energy will be increased by 4 times.

<h3>What is Wavelength?</h3>
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The distance between two objects is increased by three times the oringinal distance. How will this change the force of attractio
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<span>The distance between two objects is increased by three times the oringinal distance.  Since they were already separated by one time the original distance,
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Whether we're talking about the gravitational forces of attraction or
the electrical forces of attraction, either one is inversely proportional
to the square of the distance between the objects. 

So changing the distance to four times the original distance causes
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8 0
3 years ago
A force F acts in the forward direction on a cart of mass m. A friction force ff opposes this motion. Part A Use Newton's second
stellarik [79]

Answer:

a = F-ff/m

Explanation:

According to Newton's second law of motion which states that "the rate of change in momentum of a body is directly proportional to the applied force F and acts in the direction of the force.

Mathematically;

F = ma

Since two forces acts on the cart i.e the moving force F and the frictional force Ff , we will take the sum of the forces.

∑F = ma where

m is the mass of the cart

a is its acceleration

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F - ff = ma

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5 0
3 years ago
classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 128 feet per
ddd [48]

Answer:

t_1 = 0.28 s

t_2 = 7.72 s

Explanation:

Given that height of the projectile as a function of time is

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here we know that

h = 147 ft

so from above equation

147 = -16 t^2 + 128 t + 112

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now by solving above quadratic equation we know that

t_1 = 0.28 s

t_2 = 7.72 s

6 0
3 years ago
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