Question 3 help I don't know how to do this or what the answer is

Suppose 232subjects are treated with a drug that is used to treat pain and 50of them developed nausea. Use a 0.01significance le

Margarita [4]

Answer:

A

The correct option is B

B

$t = 0.6093$

C

$p-value = 0.27116$

D

The correct option is D

Step-by-step explanation:

From the question we are told that

The sample size is $n = 232$

The number that developed nausea is X = 50

The population proportion is p = 0.20

The null hypothesis is $H_o : p = 0.20$

The alternative hypothesis is $H_a : p > 0.20$

Generally the sample proportion is mathematically represented as

$\r p = \frac{50}{232}$

$\r p = 0.216$

Generally the test statistics is mathematically represented as

=> $t = \frac{\r p - p }{ \sqrt{ \frac{p(1- p )}{n} } }$

=> $t = \frac{ 0.216 - 0.20 }{ \sqrt{ \frac{ 0.20 (1- 0.20 )}{ 232} } }$

=> $t = 0.6093$

The p-value obtained from the z-table is

$p-value = P(Z > 0.6093) = 0.27116$

Given that the $p-value > \alpha$ then we fail to reject the null hypothesis

5 0

3 years ago

Please help with 1-9 43 points

Paul [167]

Remark

I'll do two from each group, leaving you with 1. I just leave the answer for the one I don't do or a hint it it is long. That's more than we are instructed to do (which is three parts per posted question).

One

Two ratios form a proportion because they both equal the same thing when you reduce them to the point where the ratios are prime to each other.

3/4 = 12/16

3/4 can't be reduced any further. When both 12 and 16 are divided by 4, the result is 3/4

Two

Formula

Sale Price/Original Price = 3/4

Solve

Sale Price / 64 = 3/4 Multiply both sides by 64

Sale Price = (3/4)*64

Sale Price = 48

Three

682 Trillion atoms of hydrogen.

Four

Formula

rotations / 40 seconds = rotations / second

Solve

2000 / 40 seconds = rotations / 1 second Just divide

50 rotations/1 second = rotations / second.

Five

Formula

Herd of cows / Total pounds of milk = 1 cow / pounds of milk

Given

Herd = 12

pounds total = 224998

Solve

12/224998 = 1 / x Cross multiply

12x = 224998

x = 18750 pounds of milk for 1 cow.

Six

0.5 m in 1 second.

Seven

Formula

Pages / hour = pages / minute

pages / hour = 4.5

1 hour = 60 minutes.

Solve

4.5 / 1 hour. But 1 hour = 60 min

4.5 pages / 60 min = 0.075 pages per minute.

Note this is not a true proportion. You just have to know how it is done.

Eight

This is also not a true proportion. The best way to do this is called unit analysis.

$\dfrac{18feet}{2seconds} * \dfrac{1 mile}{5280 feet}\dfrac{3600sec}{1hour}$

Each set of units on the right will cancel with a set of units on the left until all that you area left with is miles / hour. Then just multiply the numerator numbers together and denominator numbers together.

numerator: 18 * 1 * 3600 = 64800

denominator: 2 * 5280 * 1 = 10560

Now divide the numerator by the denominator.

answer: numerator/denominator = 64800/10560 = 6.14 miles per hour.

Nine

Note: there are 1760 yards in a mile.

1 gallon will take you 32000 yards or 18 miles. Do this the same way eight was done.

7 0

3 years ago

Read 2 more answers

Please help. Is algebra. PLEASE HELP NO LINKS OR FILES

olasank [31]

Answer:

1.d 2 a,d

Step-by-step explanation:

4 0

3 years ago

Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7

Nutka1998 [239]

As a Bernoulli equation:

$x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6$

Let $z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}$ . The ODE becomes

$-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6$
$x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4$
$\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4$
$x^6z=-6\displaystyle\int x^4\,\mathrm dx$
$x^6z=-\dfrac65x^5+C$
$z=-\dfrac6{5x}+\dfrac C{x^6}$
$y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}$
$y=\dfrac1{\frac C{x^6}-\frac6{5x}}$
$y=\dfrac{5x^6}{C-6x^5}$

With $y(3)=6$ , we get

$6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2$

so the solution is

$y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}$

which is valid as long as the denominator is not zero, which is the case for all $x\neq\sqrt[5]{\dfrac{4131}{12}}$ .

8 0

3 years ago

Which of the following functions is graphed below

Gwar [14]

I think the answer is C

7 0

3 years ago

Read 2 more answers