1. V = Vo + a*t.
<span>15 = 0 + a*5 a = 3 m/s^2. </span>
<span>2. V = Vo + a*t. </span>
<span>0 = 15 - 5*t, t = 3 s. </span>
<span>3. d1 = Vo*t + 0.5a*t^2. </span>
<span>Vo = 0, t = 5, a = 3 m/s^2, d1 = ?. </span>
<span>d2 = Vo*t. Vo = 15 m/s, t = 15 s, </span>
<span>d2 = ?. </span>
<span>V^2 = Vo^2 + 2a*d3. </span>
<span>V = 0, Vo = 15 m/s, a = -5 m/s^2, d3 = ?. </span>
<span>d1+d2+d3 = Total dist.</span>
Explanation:
9 × 10^-3 × 13.59 = 0.122 N
Non metals tend to have higher ionization energies
<span>0.13 miles are equal to 209 meters or 228.8 yards and the human walking speed is about 3.1 miles per hour, with all those calculations we can say that every 0.05 miles would take an average person about 1 minute, and if we add 0.10 + 0.03 it would be about 4-5 minutes to travel that short distance.</span>
Answer: a) 335.8 μm; b) keeping the same radius, the new has double potential, V=1340V so if teh radius is also double the potentail is the same (V=670V).
Explanation: In order to explain this problem we have to consider the potential given for sphere respect to infinity ( V=0) in the form:
V=k*Q/R the we have
R=k*Q/V= 9*10^9*25*10^-12/670=335.8 *10^-6 m
When two drop join to form a single drop (considering with the same radius) we have:
V=k*2Q/R
So the new V is double the original,
V=9*10^9*2*25*10^-12/335.8*10^-6=1340V
if the final single drop has a 2R of radius so
V=k*2Q/2R= 670 V
It has the same original potential.