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nadya68 [22]
3 years ago
5

Consider two different containers, each filled with 2 moles of Ne(g). One of the containers is rigid and has constant volume. Th

e other container is flexible (like a balloon) and is capable of changing its volume to keep the external pressure and inter- nal pressure equal to each other. If you raise the temperature in both containers, what happens to the pressure and density of the gas inside each container? Assume a constant external pressure.
Chemistry
1 answer:
zysi [14]3 years ago
7 0

Answer:

See explanation.

Explanation:

For the ideal gas law (PV = nRT), we can notice that when the temperatures increases, the pressure or the volume must increase.

For the container with constant volume, the pressure will increase. Because density is mass/volume, in this container the density will not change.

For the other container, the pressure must be the same as the external, so it will not change, then the volume must increase. When the volume increases, the density decreases (density = mass/volume), so the pressure doesn't change and the density decreases.

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What is the missing word in the word equation below?
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Answer:

sodium carbonate

Explanation:

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which of the following requires the most energy to break a bond? a. breaking cl-br bond. b. breaking a n-p bond. c. breaking a o
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A. Breaking a Cl-Br bond

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2 years ago
Write an overall equation for the acid-base reaction that would be required to produce the following salt. MgCl2
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7 0
3 years ago
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For the following reaction, 5.04 grams of nitrogen gas are allowed to react with 8.98 grams of oxygen gas: nitrogen(g) + oxygen(
OLga [1]

Answer:

1. 10.8 g of NO

2. N₂ is the limting reagent

3. 3.2 g of O₂ does not react

Explanation:

We determine the reaction: N₂(g) + O₂(g) →  2NO(g)

We need to determine the limiting reactant, but first we need the moles of each:

5.04 g / 29 g/mol = 0.180 moles N₂

8.98 g / 32 g/mol = 0.280 moles O₂

Ratio is 1:1, so the limiting reactant is the N₂. For 0.280 moles of O₂ I need the same amount, but I only have 0.180 moles of N₂

Ratio is 1:2. 1 mol of N₂ can produce 2 moles of NO

Then, 0.180 moles of N₂ may produce (0.180 .2) / 1 =  0.360 moles NO

If we convert them to mass → 0.360 mol . 30 g/1 mol = 10.8 g

As ratio is 1:1, for 0.180 moles of N₂, I need 0.180 moles of O₂.

As I have 0.280 moles of O₂, (0.280 - 0.180 ) = 0.100 moles does not react.

0.1 moles . 32 g/mol = 3.2 g of O₂ remains after the reaction is complete.

8 0
3 years ago
Read 2 more answers
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