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nadya68 [22]
3 years ago
5

Consider two different containers, each filled with 2 moles of Ne(g). One of the containers is rigid and has constant volume. Th

e other container is flexible (like a balloon) and is capable of changing its volume to keep the external pressure and inter- nal pressure equal to each other. If you raise the temperature in both containers, what happens to the pressure and density of the gas inside each container? Assume a constant external pressure.
Chemistry
1 answer:
zysi [14]3 years ago
7 0

Answer:

See explanation.

Explanation:

For the ideal gas law (PV = nRT), we can notice that when the temperatures increases, the pressure or the volume must increase.

For the container with constant volume, the pressure will increase. Because density is mass/volume, in this container the density will not change.

For the other container, the pressure must be the same as the external, so it will not change, then the volume must increase. When the volume increases, the density decreases (density = mass/volume), so the pressure doesn't change and the density decreases.

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3 years ago
Rory answered that absolute zero is 0°K. Is this answer correct? Explain why or why not.
Ierofanga [76]

Answer:

Yes, this answer is correct.

Explanation:

Absolute zero is -273.15 degrees celsius

T= Tc+273.15

T is the kelvin temperature

Tc is the temperature in degrees celsius

substitute;

T= -273.15 + 273.15

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3 years ago
Convert 125m^3 to km^3
Ugo [173]

Answer:

1.25e-7

Explanation:

4 0
3 years ago
Use the portion of the periodic table shown below to answer the questions.
Bingel [31]

The two elements that have the same properties as sodium are potassium  and rubidium .

<h3>What is periodic table?</h3>

The periodic table is an arrangement of the elements in order of increasing atomic number.

From the list, the two elements that have the same properties as sodium are potassium  and rubidium .

Proton has an atomic number of 20 and a mass number of 40. The number of electrons is the same as the number of protons. Given that the atomic number is the number of protons present, we have 20 electrons and 20 protons.

Number of neutrons = Mass number  - Number of protons

= 40 - 20 = 20 neutrons

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4 0
2 years ago
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
3 years ago
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