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nadya68 [22]
3 years ago
5

Consider two different containers, each filled with 2 moles of Ne(g). One of the containers is rigid and has constant volume. Th

e other container is flexible (like a balloon) and is capable of changing its volume to keep the external pressure and inter- nal pressure equal to each other. If you raise the temperature in both containers, what happens to the pressure and density of the gas inside each container? Assume a constant external pressure.
Chemistry
1 answer:
zysi [14]3 years ago
7 0

Answer:

See explanation.

Explanation:

For the ideal gas law (PV = nRT), we can notice that when the temperatures increases, the pressure or the volume must increase.

For the container with constant volume, the pressure will increase. Because density is mass/volume, in this container the density will not change.

For the other container, the pressure must be the same as the external, so it will not change, then the volume must increase. When the volume increases, the density decreases (density = mass/volume), so the pressure doesn't change and the density decreases.

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Explanation:

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From the given question;

Fischer projection for an enantiomer of 2-bromo-2,3-dihydroxypropanal with the bromine oriented horizontally to the left and the hydroxide group oriented horizontally to the right.

we can sketch the way the enantiomer of 2-bromo-2,3-dihydroxypropanal can  be seen like the one shown below:

              CH₂OH

                   |

                   |

                   |

Br -------------|----------------OH

                   |

                   |

                   |

                 CHO

The objective of this question is to drawn the perspective formula of the molecule.

So , from the attached file below; we can see the perspective formula of the molecule in a well structured 3-D format.

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