1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nadya68 [22]
3 years ago
5

Consider two different containers, each filled with 2 moles of Ne(g). One of the containers is rigid and has constant volume. Th

e other container is flexible (like a balloon) and is capable of changing its volume to keep the external pressure and inter- nal pressure equal to each other. If you raise the temperature in both containers, what happens to the pressure and density of the gas inside each container? Assume a constant external pressure.
Chemistry
1 answer:
zysi [14]3 years ago
7 0

Answer:

See explanation.

Explanation:

For the ideal gas law (PV = nRT), we can notice that when the temperatures increases, the pressure or the volume must increase.

For the container with constant volume, the pressure will increase. Because density is mass/volume, in this container the density will not change.

For the other container, the pressure must be the same as the external, so it will not change, then the volume must increase. When the volume increases, the density decreases (density = mass/volume), so the pressure doesn't change and the density decreases.

You might be interested in
Need help with 22 and 24<br>​
choli [55]

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

5 0
3 years ago
Read 2 more answers
Help me what the landform
mariarad [96]
A.) Delta . Delta is a landform that forms from Deposition.
8 0
4 years ago
Read 2 more answers
What is the reaction used to join the fatty acid to the glycerol molecule?
m_a_m_a [10]

Answer:

The reaction that is used to join fatty acid and glycerol is known as Lipogenesis.

Explanation:

Lipogenesis is an important anabolic pathway that helps in the biosynthesis of triacylglycerol by joining glycerol with fatty acid by ester linkage.Lipogenesis occur in liver and adipose tissue .

             Lipogenesis takes place in our body to store excess fatty acid in form of triacylglycerol which is a complex lipid molecule.

3 0
3 years ago
BRAINLIEST ASAP
Sveta_85 [38]

The first three quantum numbers for electrons located in subshell 4s are :

  • n = 4

  • l = 0

  • m = 0
3 0
3 years ago
Calculate the amount of energy , in Joules, required to raise the temperature of 15.5 g of liquid water from 0.00o C to 75.0 oC.
deff fn [24]

Answer:

10043.225 J

Explanation:

We'll begin by calculating the amount of heat needed to change ice to water since water at 0°C is ice. This is illustrated below:

Mass (m) = 15.5g

Latent heat of fussion of water (L) = 334J/g

Heat (Q1) =..?

Q1 = mL

Q1 = 15.5 x 334

Q1 = 5177 J

Next, we shall calculate the amount of heat needed to raise the temperature of water from 0°C to 75°C.

This is illustrated below:

Mass = 15.5g

Initial temperature (T1) = 0°C

Final temperature (T2) = 75°C

Change in temperature (ΔT) = T2 – T1 = 75 – 0 = 75°C

Specific heat capacity (C) of water = 4.186J/g°C

Heat (Q2) =?

Q2 = MCΔT

Q2 = 15.5 x 4.186 x 75

Q2 = 4866.225 J

The overall heat energy needed is given by:

QT = Q1 + Q2

QT = 5177 + 4866.225

QT = 10043.225 J

Therefore, the amount of energy required is 10043.225 J

8 0
3 years ago
Other questions:
  • Why is the formula for calcium nitride Ca3N2?
    13·1 answer
  • The element sodium occurs naturally as a light solid with shiny metallic appearance. The diagram shows what will happen when a p
    9·1 answer
  • A 20.0–milliliter sample of 0.200–molar K2CO3 so­lution is added to 30.0 milliliters of 0.400–mo­lar Ba(NO3)2 solution. Barium c
    7·1 answer
  • The atomic mass is important because
    7·1 answer
  • How many mL are in 7.3 dL?
    6·1 answer
  • What happens when a piece of Mg ribbon is burnt? Name the
    10·1 answer
  • The length of a year is equivalent to the time it takes for one.. (pls help I honestly forgot )
    13·1 answer
  • Can someone answer these for me I’ll mark you brainliset or whatever it’s called lol I rlly need to get these right
    15·1 answer
  • What are the common properties of the following element groups:
    14·1 answer
  • Besides drinking water, how is water helpful for life and nature?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!