The equilibria showing how the acetate buffer adjusts to addition of a small amount of NaOH is:
- CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)
<h3>What is a buffer?</h3>
A buffer is a solution which resists changes to its pH when small amounts of strong base or acid is added to it.
Buffers are made from solutions of weak acids and their salts or weak bases and their salts.
The equilibria showing how a buffer made from acetic acid and sodium acetate (NaCH3COO) adjusts to addition of a small amount of NaOH is as follows:
- CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)
Addition of NaOH, a strong base will neutralize the hydronium ion, causing the acetic acid ionization equilibrium to shift to the right to produce more of the acetate ion, the conjugate base.
Learn more about acetate buffer at: brainly.com/question/17490438
Answer:
The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)
Explanation:
Step 1: Data given
2.0 M Al(NO3)3
Step 2:
Al(NO3)3 in water will dissociate as following:
Al(NO3)3 → Al^3+ + 3NO3^-
For 1 mol of Al(NO3)3 we will have 1 mol of Al^3+ and 3 moles of NO3^-
We know that the molarity of Al(NO3)3 = 2.0 M, this means 2.0 mol/ L
The mol ratio Al(NO3)3 and Al^3+ is 1:1 so the molarity of Al^3+ is<u> 2.0 M</u>
The mol ratio Al(NO3)3 and NO3^- is 1:3 so the molarity of NO3^- is<u> 6.0M</u>
The correct answer is: 2M Al3+(aq) and 6 M NO3-(aq)
No I can’t
EXAMPLE took the test k12
Distillation is by definition separation by boiling point. Basically things that have lower boiling points will boil before things that have higher boiling points. so if you go into the temperature range between the two boiling points, one will boil and vaporize and one will remain a liquid (maybe solid).
