Answer:
Option-A [<span>Cl (g) + e</span>⁻ <span> → Cl</span>⁻<span> (g)] is the correct answer.
Explanation:
First electron affinity is the amount of heat evolved when an electron is added to a neutral atom.
Such problems often come in questions related to Born-Haber Cycle topic. Let suppose Mg and Cl</span>₂ is reacted to form<span> MgCl</span>₂ crystal.
Then the Cl₂ gas is first atomized as follow,
Cl₂ → 2 Cl
After atomization an electron is added to neutral chlorine atoms, as,
Cl + e⁻ → Cl⁻
So, option A is correct choice.
Answer:
The concentration of COF₂ at equilibrium is 0.296 M.
Explanation:
To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
I 2.00 0 0
C -2x +x +x
E 2.00 - 2x x x
Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".
![Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852](https://tex.z-dn.net/?f=Kc%3D8.30%3D%5Cfrac%7B%5BCO_%7B2%7D%5D%20%5Ctimes%20%5BCF_%7B4%7D%5D%20%7D%7B%5BCOF_%7B2%7D%5D%5E%7B2%7D%20%7D%20%3D%5Cfrac%7Bx%5E%7B2%7D%20%7D%7B%282.00-2x%29%5E%7B2%7D%20%7D%20%5C%5C8.30%3D%28%5Cfrac%7Bx%7D%7B2.00-2x%7D%20%29%5E%7B2%7D%20%5C%5C%5Csqrt%7B8.30%7D%20%3D%5Cfrac%7Bx%7D%7B2.00-2x%7D%5C%5C5.76-5.76x%3Dx%5C%5Cx%3D0.852)
The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M
1) Assume M refers to a general element and Z referes to other general element.
2) Assume the chemical formula of the ionic compound is MₓZₐ
3) Then the dissociaton would be written:
MₓZₐ → XMᵃ⁺ + AZˣ⁻
That means that the ionic compoud will lead to the X cations Mᵃ⁺ whose oxidation state are a+, and A anions Zˣ⁻ whose oxidation state is x⁻.
5) For example: MgBr₂ (aq) → Mg⁺² (aq) + 2Br⁻ (aq)
6) Explanation: since the water molecules are polar, they will surround (solvate) the three ions that form the compound MgBr₂, overcoming the electrostatic forces that hold together the atoms in the ionic lattice.
Answer:
4.8 grams
Explanation:
Use PV=nRT
P: 775 mmHg (divide by 760 mmHg to get atm) -> 1.02 atm
V: 3700 mL (divide by 1000 to get L) -> 3.7L
n: ?
R: (a constant) 0.0821L * atm/k *mol
T: 33 C (add 273 to get K) -> 306K
Move equation so n is on the side: PV/RT = n. Plug the numbers into the equation.
Then, convert moles to grams using the molar mass of O2 which is 32g/mol.
= 4.8g
