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Aleksandr-060686 [28]
3 years ago
8

Help help help help help help​

Chemistry
1 answer:
natita [175]3 years ago
3 0

Hey,

Answer:

<em>AgCl</em><em> </em>(Silver Chloride)

Explanation:

sodium chloride + silver nitrate → sodium nitrate+ silver chloride

Hope it helps :)

Have a great day!

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Which equation represents the first electron affinity of chlorine?
mars1129 [50]
Answer:
            Option-A [<span>Cl (g) + e</span>⁻ <span> →  Cl</span>⁻<span> (g)] is the correct answer.

Explanation:
                   First electron affinity is the amount of heat evolved when an electron is added to a neutral atom.
                   Such problems often come in questions related to Born-Haber Cycle topic. Let suppose Mg and Cl</span>₂ is reacted to form<span> MgCl</span>₂ crystal.

Then the Cl₂ gas is first atomized as follow,

                                        Cl₂     →     2 Cl

After atomization an electron is added to neutral chlorine atoms, as,

                                      Cl  +  e⁻    →     Cl⁻

So, option A is correct choice.
7 0
3 years ago
Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it
Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

   2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I      2.00              0              0

C      -2x              +x            +x

E   2.00 - 2x         x              x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

6 0
3 years ago
Need help with this.
ankoles [38]
The answer would be D!
3 0
3 years ago
Read 2 more answers
How would an equation be written for the dissociation of ionic solutes in water?
tangare [24]
1) Assume M refers to a general element and Z referes to other general element.

2) Assume the chemical formula of the ionic compound is MₓZₐ

3) Then the dissociaton would be written:


MₓZₐ → XMᵃ⁺ + AZˣ⁻

That means that the ionic compoud will lead to the X cations Mᵃ⁺ whose oxidation state are a+, and A anions Zˣ⁻ whose oxidation state is x⁻.

5) For example: MgBr₂ (aq) → Mg⁺² (aq) + 2Br⁻ (aq)


6) Explanation: since the water molecules are polar, they will surround (solvate) the three ions that form the compound MgBr₂, overcoming the electrostatic forces that hold together the atoms in the ionic lattice.



3 0
4 years ago
How many grams of O2 gas are in a 3700 mL container at a pressure of 775 mmHg at 33oC?
Zina [86]

Answer:

4.8 grams

Explanation:

Use PV=nRT

P: 775 mmHg (divide by 760 mmHg to get atm)  -> 1.02 atm

V: 3700 mL (divide by 1000 to get L)  -> 3.7L

n: ?

R: (a constant) 0.0821L * atm/k *mol

T: 33 C (add 273 to get K)  -> 306K

Move equation so n is on the side: PV/RT = n. Plug the numbers into the equation.

\frac{1.02atm * 3.7L }{306K} * \frac{K * mol}{0.0821L *atm} = 0.15 mol

Then, convert moles to grams using the molar mass of O2 which is 32g/mol.

0.15 mol * \frac{32g}{mol}= 4.8g

5 0
2 years ago
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