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Gelneren [198K]
3 years ago
6

What should a consumer consider when shopping for a credit card? Check all that apply.

Chemistry
2 answers:
Svetlanka [38]3 years ago
7 0
The initial fees to open the account.
The fees charged for late payment.
The annual percentage rate for the card.
Marina CMI [18]3 years ago
4 0

Answer:

B. the initial fees to open the account

C. the fees charged for late payments

E. the annual percentage rate for the card

Explanation:

Edg

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Which of the following describes a spectrum?
natka813 [3]

Answer: The Answer would be C

Explanation: A spectrum is a Range of Wavelengths and Frequencies of Electromagnetic Radition.

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Suppose a vodka martini contains 30% alcohol with the remaining portion of the drink composed of water. what is the solute in th
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Solute - substance that dissolves. 
alcohol - solute
water - solvent
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What is the smallest component or the most basic building block of any element ? A. An Atom, B.a compound C.gas D.element
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The answer to the question is A) an atom.


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What happens when an electron absorbs energy? A. The electron moves from a lower energy orbital to a higher energy orbital. B. T
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A. The electron moves from a lower to a higher energy orbital
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Calculate the ph for each case in the titration of 50.0 ml of 0.150 m hclo(aq) with 0.150 m koh(aq). use the ionization constant
Lena [83]
<h3><u>Answer</u>;</h3>

pH =7.58

<h3><u>Explanation;</u></h3>

The KOH will react with the HClO to produce KClO. You will have a solution containing unreacted HClO and KOH. This is a buffer solution.  

Equation:  

HClO + KOH → KClO + H2O  

HClO reacts with KOH in 1:1 molar ratio  

Mol HClO in 50mL of 0.150M solution = 50/1000*0.150 = 0.0075 mol HClO  

Mol KOH in 30mL of 0.150M solution = 30/1000*0.150 = 0.0045 mol KOH  

These react to produce 0.0045 mol KClO and there is 0.0030 mol HClO unreacted  

Volume of solution = 50mL + 30mL = 80mL = 0.080L  

Molarity of HClO in solution = 0.0030/0.080 = 0.0375M  

Molarity of KClO in solution = 0.0045/0.080 = 0.0562M  

Using the Henderson-Hasselbalch equation we can calculate the pH;  

pKa HClO = -log ( 4.0*10^-8) = 7.40  

pH = pKa + log ([KClO]/[HClO])  

pH = 7.40 + log( 0.0562/0.0375)  

pH = 7.40 + log 1.50  

pH = 7.40+ 0.18  

pH = 7.58

7 0
4 years ago
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