Http://www.geologyin.com/2014/11/how-to-identify-minerals-in-10-steps.html
Answer:
5 L
Explanation:
We'll begin by calculating the molarity of the CaCl₂ solution. This can be obtained as follow:
Mole of CaCl₂ = 0.5 mole
Volume = 2 L
Molarity =?
Molarity = mole /Volume
Molarity = 0.5 / 2
Molarity = 0.25 M
Finally, we shall determine the volume of the diluted solution. This can be obtained as follow:
Molarity of stock solution (M₁) = 0.25 M
Volume of stock solution (V₁) = 2 L
Molarity of diluted solution (M₂) = 0.1 M
Volume of diluted solution (V₂) =?
M₁V₁ = M₂V₂
0.25 × 2 = 0.1 × V₂
0.5 = 0.1 × V₂
Divide both side by 0.1
V₂ = 0.5 / 0.1
V₂ = 5 L
Thus the volume of the diluted solution is 5 L
Answer:
1.67×10^-1
Explanation:
Use the formula n=m/R.M.M
Find the R.M.M. Formula of the compound is AgNO3.
So Ag mass is 108, N mass is 14, and O mass is 16.
So 108+14+(16×3)=170.
Than use formula n=28.39/170 giving 0.167. In scientific notation 1.67×10^-1.
I think
