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AfilCa [17]
3 years ago
11

At high altitudes, mountaineers cannot absorb a sufficient amount of O2 in your flows blood to maintain a high level of activity

. a pressure of 1 bar, the blood is typically saturated at 95% O2 but at 18,000 feet where the pressure is 0.50 , the corresponding degree of saturation is 71%. Assuming that Henry's law constant for blood is the same as for water, calculate the amount of O dissolved in 1.00 L of blood for pressures of 1 bar and Pub. Air contains 20.99% O2 in volume. Suppose the density of blood is 998 kg m -3
Engineering
1 answer:
Free_Kalibri [48]3 years ago
3 0
What’s the question?
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A particular NMOS device has parameters VT N = 0.6 V, L = 0.8µm, tox = 200 Å, and µn = 600 cm2 /V–s. A drain current of ID = 1.2
NeTakaya

Answer:

W= 3.22 \mu m

Explanation:

the transistor In saturation drain current region is given by:

i_D}=K_a(V_{GS}-V_{IN})^2

Making K_a the subject of the formula; we have:

K_a=\frac {i_D} {(V_{GS} - V_{IN})^2}

where;

i_D = 1.2m

V_{GS}= 3.0V

V_{TN}  = 0.6 V

K_a=\frac {1.2m} {(3.0 - 0.6)^2}

K_a = 208.3 \mu A/V^2

Also;

k'_n}=\frac{\mu n (\frac{cm^2}{V-s} ) \epsilon _{ox}(\frac{F}{cm} ) }{t_{ox}(cm)}

where:

\mu n (\frac{cm^2}{V-s} ) = 600

\epsilon _{ox}=3.9*8.85*10^{-14}

{t_{ox}(cm)=200*10^{-8}

substituting our values; we have:

k'_n}=\frac{(600)(3.988.85*10^{-14})}{(200*10^{-8})}

k'_n}=103.545 \mu A/V^2

Finally, the width can be calculated by using the formula:

W= \frac{2LK_n}{k'n}

where;

L = 0.8 \mu m

W= \frac{2*0.8 \mu m *208.3 \mu}{103.545 \mu}

W= 3.22 \mu m

4 0
4 years ago
This came off my car earlier today. What is it and what does it do?
patriot [66]

Answer:

get a new car or duck tape it back on or go get it fixed

Explanation:

that's just whut I wold do.

6 0
3 years ago
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Imagine you are designing a new backpack. Which of the following statement(s) about
Hoochie [10]
The answer is D.) both A and C
3 0
3 years ago
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What should i do to my nissan 350z, twin charge it or have twin turbos, to twin turbos with a super charger? i want it to be ove
bulgar [2K]

Answer:

A

Explanation:

It just makes sense

4 0
3 years ago
From the following numbered list of characteristics, decide which pertain to (a) precipitation hardening, and which are displaye
tia_tia [17]

Answer:

(a) Precipitation hardening - 1, 2, 4

(b) Dispersion strengthening - 1, 3, 5

Explanation:

The correct options for each are shown as follows:

Precipitation hardening

From the first statement; Dislocation movement is limited by precipitated particles. This resulted in an expansion in hardness and rigidity. Precipitates particles are separated out from the framework after heat treatment.

The aging process occurs in the second statement; because it speaks volumes on how heated solutions are treated with alloys above raised elevated temperature. As such when aging increases, there exists a decrease in the hardness of the alloy.

Also, for the third option for precipitation hardening; This cycle includes the application of heat the alloy (amalgam) to a raised temperature, maintaining such temperature for an extended period of time. This temperature relies upon alloying components. e.g. Heating of steel underneath eutectic temperature. Subsequent to heating, the alloy is extinguished and immersed in water.

Dispersion strengthening

Here: The effect of hearting is not significant to the hardness of alloys hardening by the method in statement 3.

In statement 5: The process only involves the dispersion of particles and not the application of heat.

8 0
3 years ago
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