Answer:
45 Mpa
Explanation:
The maximum shear stress, 
is given by
Where T is the torque and d is the diameter.
Substituting 29820.586 N.m for T and 0.15m for d then we obtain
Explanation:
def checklist(a_list, a_value):// def //used to name a function, the //arguments being passed into the //functions are a_list and a_value
if a_value in list://if statement to
//check if it's in the list or not
print("")//print statement to do
//nothing
else://else statement for if the
//a_value is in a_list
a_list.append(a_value)//this adds
//the value to the list
Answer:
Employers must comply with OSHA's regulations to safeguard workers from caught-in or -between dangers, which include, but are not limited to, the following:
• Protect power tools and other equipment with moving parts with guards.
• Support, secure, or otherwise make safe any equipment that has pieces that workers could become entangled in.
· Take precautions to avoid workers being crushed by tipped-over heavy machinery.
• Take precautions to avoid pinning workers between equipment and a solid object.
• Provide workers with protection when trenching and excavating.
• Provide ways to prevent constructions, such as scaffolds, from collapsing.
Explanation:
Answer:
(a) E = 0 N/C
(b) E = 0 N/C
(c) E = 7.78 x10^5 N/C
Explanation:
We are given a hollow sphere with following parameters:
Q = total charge on its surface = 23.6 μC = 23.6 x 10^-6 C
R = radius of sphere = 26.1 cm = 0.261 m
Permittivity of free space = ε0 = 8.85419 X 10−12 C²/Nm²
The formula for the electric field intensity is:
E = (1/4πεo)(Q/r²)
where, r = the distance from center of sphere where the intensity is to be found.
(a)
At the center of the sphere r = 0. Also, there is no charge inside the sphere to produce an electric field. Thus the electric field at center is zero.
<u>E = 0 N/C</u>
(b)
Since, the distance R/2 from center lies inside the sphere. Therefore, the intensity at that point will be zero, due to absence of charge inside the sphere (q = 0 C).
<u>E = 0 N/C</u>
(c)
Since, the distance of 52.2 cm is outside the circle. So, now we use the formula to calculate the Electric Field:
E = (1/4πεo)[(23.6 x 10^-6 C)/(0.522m)²]
<u>E = 7.78 x10^5 N/C</u>
