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SpyIntel [72]
2 years ago
14

To protect their employees from caught-in and -between hazards, what must employers do?

Engineering
1 answer:
marusya05 [52]2 years ago
5 0

Answer:

Employers must comply with OSHA's regulations to safeguard workers from caught-in or -between dangers, which include, but are not limited to, the following:

• Protect power tools and other equipment with moving parts with guards.

• Support, secure, or otherwise make safe any equipment that has pieces that workers could become entangled in.

· Take precautions to avoid workers being crushed by tipped-over heavy machinery.

• Take precautions to avoid pinning workers between equipment and a solid object.

• Provide workers with protection when trenching and excavating.

• Provide ways to prevent constructions, such as scaffolds, from collapsing.

Explanation:

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If coolant is mixed 50-50 with water, what is the freezing point?
sashaice [31]

Answer:

-35 degrees F

When mixed in equal parts with water (50/50), antifreeze lowers the freezing point to -35 degrees F and raises the boiling temperature to 223 degrees F. Antifreeze also includes corrosion inhibitors to protect the engine and cooling system against rust and corrosion.

8 0
3 years ago
Which factor has the most significant impact in design?
wariber [46]

D) cost


The fund available for a project is the first factor to be considered to ensure that the project comes to reality and serve it’s purpose

3 0
2 years ago
Advantage and disadvantages of Bessemer process of steel making
Snowcat [4.5K]

Advantages:

- allowed steel to be produced without fuel

- using the impurities of the iron to create the necessary heat

- reduced the costs of steel production

Disadvantages:

- could convert only a pig iron low in phosphorus and sulfur

- these elements could have been removed by adding a basic flux such as lime, but the basic sl*g produced would have degraded the acidic refractory lining of Bessemer's converter.

au revoir mon amour <3

7 0
2 years ago
Steam enters a turbine from a 2 inch diameter pipe, at 600 psia, 930 F, with a velocity of 620 ft/s. It leaves the turbine at 12
Katarina [22]

Answer:

\dot W_{out} = 3374.289\,\frac{BTU}{s}

Explanation:

The model for the turbine is given by the First Law of Thermodynamics:

- \dot W_{out} + \dot m \cdot (h_{in} - h_{out}) = 0

The turbine power output is:

\dot W_{out} = \dot m\cdot (h_{in}-h_{out})

The volumetric flow is:

\dot V = \frac{\pi}{4} \cdot \left( \frac{2}{12}\,ft \right)^{2}\cdot (620\,\frac{ft}{s} )

\dot V \approx 13.526\,\frac{ft^{3}}{s}

The specific volume of steam at inlet is:

State 1 (Superheated Steam)

\nu = 1.33490\,\frac{ft^{3}}{lbm}

The mass flow is:

\dot m = \frac{\dot V}{\nu}

\dot m = \frac{13.526\,\frac{ft^{3}}{s} }{1.33490\,\frac{ft^{3}}{lbm} }

\dot m = 10.133\,\frac{lbm}{s}

Specific enthalpies at inlet and outlet are, respectively:

State 1 (Superheated Steam)

h = 1479.74\,\frac{BTU}{lbm}

State 2 (Saturated Vapor)

h = 1146.1\,\frac{BTU}{lbm}

The turbine power output is:

\dot W_{out} = (10.133\,\frac{lbm}{s} )\cdot (1479.1\,\frac{BTU}{lbm}-1146.1\,\frac{BTU}{lbm})

\dot W_{out} = 3374.289\,\frac{BTU}{s}

6 0
3 years ago
Calculate the power required for heating a 1.5 kg sample of water for 10 minutes in a thermal system. What is the amount of ener
Masja [62]

Answer:

Power= Heat energy\ time

heat energy= mc∆T

specific heat of water = 4180

1.5*4180*(60-25)

=219450

time = 10× 60= 600 secs

power = 219450/600

Power= 365.75 Watt

=0.37 KW

Explanation:

the actual has to be bigger because the heater might be required to handle more ...also to accommodate extra energy.

5 0
2 years ago
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