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pantera1 [17]
3 years ago
9

why does a car slide when it rolls over an icy patch on a road? A. cars have more momentum on icy surfaces. B. there is less fri

ction between the cars tires and the ice than between the car tires and the road. C. there is more friction between the cars tires and the ice than between the car tires and the road. D. cars have less momentum on icy surfaces.
Physics
2 answers:
Vaselesa [24]3 years ago
6 0
The answer is B
because if you compare a regular road and ice... ice is smoother and therefore has less friction 
sweet-ann [11.9K]3 years ago
6 0
B) because a road is usually covered in rocks which increases the friction, but since its now covered in ice which is usually a smooth surface is has less friction leading to the car sliding. Also if the top of the ice has melted it may hav left behind water and hitch is a lubricant and reduces friction
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Wilbur ran 1-kilometer. Then he ran 500 meters. How many meters did Wilbur run all together?
Blababa [14]
The answer is B 1,500 meters since 1 kilometer to meters is 1,000 and u add the 500
8 0
3 years ago
Un automovil parte del reposo y acelera uniformemente hasta alcanzar una rapidez de 0,255km/h en un tiempo de 3/4 Minutos determ
Elden [556K]

Answer:

a = 1.5*10^-3 m/s^2

x = 0.033m = 3.3cm

Explanation:

To calculate the acceleration and the distance traveled by the car you use the following formulas:

v=v_o+at    (1)

x=v_ot+\frac{1}{2}at^2   (2)

v: final velocity = 0,255 km/h

vo: initial velocity = 0 m/s

t: time = 3/4 min

a: acceleration = ?

x: distance

In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

v=0,255\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}\\\\v=0.07m/s\\\\t=\frac{3}{4}min*\frac{60s}{1min}=45s

Next, you solve the equation (1) for the acceleration a:

a=\frac{v}{t}=\frac{0.07m/s}{45s}=1.5*10^{-3}\frac{m}{s^2}

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

x=\frac{1}{2}(1.5*10^{-3}m/s^2)(45s)^2=0.033m=3.3cm

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m

5 0
4 years ago
A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.
ella [17]

Answer:

a. 17 μC b. 14.45 J

Explanation:

Here is the complete question

A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.

a. What charge is stored in each capacitor?

b. How much energy is stored in each capacitor?

a. The charge Q stored in a capacitor is Q = CV where C = capacitance  and V = voltage. Here, C = 10μF = 10 × 10⁻⁶ F and V = 1.7 kV = 1.7 × 10³ V.

So, Q = CV = 10 × 10⁻⁶ × 1.7 × 10³ = 1.7 × 10⁻² C = 17 × 10⁻³ C = 17 μC

b. The energy stored in a capacitor is given by W = 1/2CV² = 1/2 × 10 × 10⁻⁶ F × (1.7 × 10³ V)² =  1/2 × 10 × 10⁻⁶ F × 2.89 × 10⁶ V² = 1/2 × 10 × 2.89 × 10⁶ × 10⁻⁶ J = 14.45 J

8 0
3 years ago
A hard rubber ball is thrown level to the ground at a speed of 25 m/s and an initial height of 2.0 meters. Which best describes
Natali [406]
Yes 25.7677 is the amount of motion
7 0
4 years ago
A large ball of gas that is held together by gravity and that has a core so hot that
valentina_108 [34]
The answer is a star
4 0
2 years ago
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