The answer is B 1,500 meters since 1 kilometer to meters is 1,000 and u add the 500
Answer:
a = 1.5*10^-3 m/s^2
x = 0.033m = 3.3cm
Explanation:
To calculate the acceleration and the distance traveled by the car you use the following formulas:
(1)
(2)
v: final velocity = 0,255 km/h
vo: initial velocity = 0 m/s
t: time = 3/4 min
a: acceleration = ?
x: distance
In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.

Next, you solve the equation (1) for the acceleration a:

With this value of a you can calculate the distance traveled by the car, by using the equation (2):

hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m
Answer:
a. 17 μC b. 14.45 J
Explanation:
Here is the complete question
A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.
a. What charge is stored in each capacitor?
b. How much energy is stored in each capacitor?
a. The charge Q stored in a capacitor is Q = CV where C = capacitance and V = voltage. Here, C = 10μF = 10 × 10⁻⁶ F and V = 1.7 kV = 1.7 × 10³ V.
So, Q = CV = 10 × 10⁻⁶ × 1.7 × 10³ = 1.7 × 10⁻² C = 17 × 10⁻³ C = 17 μC
b. The energy stored in a capacitor is given by W = 1/2CV² = 1/2 × 10 × 10⁻⁶ F × (1.7 × 10³ V)² = 1/2 × 10 × 10⁻⁶ F × 2.89 × 10⁶ V² = 1/2 × 10 × 2.89 × 10⁶ × 10⁻⁶ J = 14.45 J