Question

Your roommate is working on his bicycle and has the bike upside down. He spins the 68.0 cm -diameter wheel, and you notice that a pebble stuck in the tread goes by three times every second. A. What is the pebble's speed? B. What is the pebble's acceleration?

Answer 1

Answer:

a. 6.41 m/s

b. 120.85 m/s^2

Explanation:

The computation is shown below:

a. Pebble speed is

As we know that according to the tangential speed,

$v = r \times \omega$

$= \frac{0.68}{2} \times 18.84$

= 6.41 m/s

The 18.84 come from

$= 2 \times 3.14 \times 3$

= 18.84

b. The pebble acceleration is

$a = \frac{v^2}{r}$

$= \frac{6.41^2}{0.34}$

= 120.85 m/s^2

We simply applied the above formulas so that the pebble speed and the pebble acceleration could come and the same is to be considered