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IRINA_888 [86]
4 years ago
14

A team of engineering students is designing a catapult to launch a small ball at A so that it lands in the box. If it is known t

hat the initial velocity vector makes a 32° angle with the horizontal, determine the range of launch speeds for which the ball will land inside the box.
Physics
1 answer:
Murljashka [212]4 years ago
8 0

Answer:

Explanation:

If the initial velocity is U

Then the horizontal component of the velocity is

Ux= Ucosθ

Then the range for a projectile is give as

R=Ux.t

Where t is the time of flight

The time of flight is given as

t=2USinθ/g

Therefore,

R=Ux.t

R=UCosθ.2USinθ/g

R=U^2×2SinθCosθ/g

Then, from trigonometric ratio

2SinθCosθ= Sin2θ

R=U^2Sin2θ/g

Given that θ=32° and g=9.81m/s^2

Then

R=U^2Sin2×32/9.81

R=U^2Sin64/9.81

R=0.0916U^2

Then, range is given by R=0.0916U^2

A=0.0916U^2.

T

The box is at a distance A from the point of projection. Then the range R=A

R=0.0916U^2

A=0.0916U^2

Then,

U^2=A/0.0916

U^2=10.915A

Then the initial velocity should be

U=√10.915A

U=3.3√A

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If a flea can jump straight up to a height of 0.550 m , what is its initial speed as it leaves the ground?
olga55 [171]
Let u = upward initial speed of the flea.

At the maximum height of h = 0.550 m, the vertical velocity is v = 0.
Therefore, from the formula
 v² = u² - 2gh,
obtain
0 = u² - 2*(9.8 m/s²)*(0.55 m) 
u² = 10.78 m²/s²
 u = 3.283 m/s

Answer: The initial upward speed is 3.28 m/s (nearest thousandth)

7 0
3 years ago
A plane leaves the airport in Galisteo and flies 170 km at 68.0° east of north; then it changes direction to fly 230 km at 36.0°
luda_lava [24]

Answer:

The direction will be 84.86^\circ and the distance 250.75km.

Explanation:

Let's say A is the displacement vector which represents the first 170km and B the one for the next 230km. Then the components of these vector will be:

A_x=170cos(68^{\circ})\\ A_y=170sin(68^\circ)\\\\B_x=230cos(-36^\circ)\\B_y=230sin(-36^\circ)

The vector which point from the origin to the final position of the plane will be R=A+B. We sum components on <em>x </em>and <em>y </em>independetly (vector property):

R_x=A_x+B_x=170cos(68^{\circ})+230cos(-36^\circ)=63.68km+186.07km=249.75km

R_y=A_y+B_y=170sin(68^\circ)+230sin(-36^\circ)=157.62km-135.19km=22.43km

If \theta is the direction of R then:

tan(\theta )=\frac{R_x}{R_y} ⇒ \theta = arctan(\frac{R_x}{R_y}) ⇒ \theta = 84.86^\circ.

The distance will be given by the magnitud of the vector R:

R=\sqrt{R_x^2 + R_y^2} ⇒ R=\sqrt{R_x^2 + R_y^2} = 250.75.

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4 years ago
Pls help me I want to get this done
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8 0
3 years ago
The biodiversity of cultivated crops is currently under threat
Angelina_Jolie [31]

C. Establishing a seed bank with a variety of seeds of

different crop species

Explanation:

Establishing a seed bank with a variety of seeds of different crop species is a cooperative behavior that would best enable humans to prevent the problem of loss of biodiversity of cultivated crops.

  • Modern agricultural practices is profit driven and centered on mono-cropping.
  • Mono-cropping is an agricultural practice in which only one crop type is cultivated on a mechanized scale.
  • Mono-cropping leads to less diversity of crop species as just only the cultivation of economically important crops are encouraged.
  • In order to avert the menace that comes along with mono-cropping, seed banks are viable place to keep and protect other plant species from going into extinction.
  • Seed banks provides a preservation of different plant species by focusing on storing their viable seeds.

Learn more:

Inhumane farming brainly.com/question/4674681

#learnwithBrainly

4 0
3 years ago
Read 2 more answers
Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find
AysviL [449]

Answer:

A. The box experiences more friction on the carpeted floor

Explanation:

Friction is the force that opposes the motion of an object when it slides along a surface. The magnitude of the friction is given by

F=\mu mg

where m is the mass of the object, g is the acceleration due to gravity, and \mu is the coefficient of friction, which depends on the type of material of the surface: the larger this coefficient, the stronger the friction, the more difficult is to push the box along the surface. Generally, a smooth surface has a lower coefficient of friction, while a rough surface has a larger coefficient of friction.

In this case, Ethan find it easier to push the box on the marble floor, because marble is smoother than the carpet and so friction is weaker, while for the carpeted floor the coefficient of friction is larger and so the friction is stronger, making it more difficult to push the box.

3 0
3 years ago
Read 2 more answers
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