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Pavel [41]
3 years ago
13

As the plates continues to grind against each other,what geologic events could take place

Physics
2 answers:
motikmotik3 years ago
8 0
<span>As the plates continue to grind against each other the geologic events could take place is the Earthquake

Explanation
:
</span>
An earthquake (also called<span> a quake, tremor or temblor) </span>is that the<span> shaking of the surface of </span>the planet<span>, </span>ensuing<span> from the </span><span>sudden </span>release<span> of energy </span>within the<span> Earth's </span>layer that makes unstable<span> waves.
Earthquakes </span>will point<span> size from </span>those who are therefore weak<span> that </span>they can not<span> be felt to those violent enough to toss </span>people<span> around and destroy whole cities.
The seismicity, or </span>unstable activity<span>, of </span>an area, is that the<span> frequency, </span>sort<span> and size of earthquakes </span>practised<span> over an </span>amount of your time<span>. </span>

<span>The phenomena of the tectonic drifts </span>it isn't<span> forever and at one </span>purpose can<span> stop.
The </span>results of<span> what you </span>call<span> grind are earthquakes, erosion, land formation, Tectonic movement into the ocean or out of the ocean.

This </span>development can<span> continue </span>until purpose<span> that, a gap between the crust and </span>mantle are going to be massive<span> enough to clap the crust into the </span><span>mantel.</span>

-BARSIC- [3]3 years ago
3 0
As tectonic plates continue to grind against each other, the most common event that can take place would be an Earthquake, although volcanic eruptions can also occur. 
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vekshin1

Answer:

P = 24.32 W

Explanation:

The question is, "Two resistors 5 Ω and 10 Ω are connected in parallel with a 9 V power supply. Calculate the output power of the power supply.".

The voltage of the power supply, V = 9 V

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The equivalent of parallel combination of resistors is given by :

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\\\dfrac{1}{R_{eq}}=\dfrac{1}{5}+\dfrac{1}{10}\\\\R_{eq}=3.33\ \Omega

The power of the output is given by :

P=\dfrac{V^2}{R_{eq}}\\\\=\dfrac{9^2}{3.33}\\\\P=24.32\ W

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