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2 years ago

As the plates continues to grind against each other,what geologic events could take place

2 answers:

8 0

As the plates continue to grind against each other the geologic events could take place is the Earthquake

Explanation:

An earthquake (also called a quake, tremor or temblor) is that the shaking of the surface of the planet, ensuing from the sudden release of energy within the Earth's layer that makes unstable waves.
Earthquakes will point size from those who are therefore weak that they can not be felt to those violent enough to toss people around and destroy whole cities.
The seismicity, or unstable activity, of an area, is that the frequency, sort and size of earthquakes practised over an amount of your time. 

The phenomena of the tectonic drifts it isn't forever and at one purpose can stop.
The results of what you call grind are earthquakes, erosion, land formation, Tectonic movement into the ocean or out of the ocean.

This development can continue until purpose that, a gap between the crust and mantle are going to be massive enough to clap the crust into the mantel.

-BARSIC- [3]2 years ago

3 0

As tectonic plates continue to grind against each other, the most common event that can take place would be an Earthquake, although volcanic eruptions can also occur.

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A playground merry-go-round of radius R = 1.40 m has a moment of inertia I = 265 kg · m2 and is rotating at 11.0 rev/min about a

Tom [10]

Answer:

The value of new value of angular speed of merry go round. $\omega_{2}$ = 0.96 $\frac{rad}{sec}$

Explanation:

Given data

r = 1.4 m

Moment of inertia $I_{1}$ = 265 kg - $m^{2}$

$N_{1} =$ 11 RPM

$\omega_{1} = \frac{2 \pi N}{60}$

$\omega_{1} = \frac{2 \pi (11)}{60}$

$\omega_{1}$ = 1.15 $\frac{rad}{sec}$

From conservation of momentum principal

$I_{1} \omega_{1} = I_{2} \omega_{2}$ ------- (1)

$I_{2} = m r^{2} + 265$

$I_{2} = 27 (1.4)^{2} + 265$

$I_{2} = 317.92 \ kg m^{2}$

Put all the values in equation (1)

265 × 1.15 = 317.92 × $\omega_{2}$

$\omega_{2}$ = 0.96 $\frac{rad}{sec}$

This is the value of new value of angular speed of merry go round.

6 0

2 years ago

If you shine a light of frequency 375hz on a double slit setup , and you measure the slit separation to be 950 nm and the screen

amm1812

Answer:

y = 33.93 10⁵ m

Explanation:

This is an interference exercise, for the contributory interference is described by the expression

d sin θ = m λ

let's use trigonometry for the angle

tan θ = y / L

how the angles are small

tan θ = sin θ / cos tea = sin θ

we substitute

sin θ = y / L

d y / L = m λ

y = m λ L / d

the light fulfills the relation of the waves

c = λ f

λ = c / f

λ = 3 10⁸ /375

λ = 8 10⁵ m

first order m = 1

let's calculate

y = 1 8 10⁵ 4030 10-9 / 950 10-9

y = 33.93 10⁵ m

6 0

2 years ago

John accidentally drops his keys off the balcony at his apartment. John's friend Tony just happens to walk by at that moment and

EleoNora [17]

Explanation:

In order to find out if the keys will reach John or not, we can use the formula of projectile motion to find the maximum height reached by the keys:

H = V²Sin²θ/2g

where,

V = Launch Speed = 18 m/s

θ = Launch Angle = 40°

g = 9.8 m/s²

Therefore,

H = (18 m/s)²[Sin 40°]²/(2)(9.8 m/s²)

H = 6.83 m

Hence, the maximum height that can be reached by the projectile or the keys is greater than the height of John's Balcony(5.33 m).

Therefore, the keys will make it back to John.

7 0

2 years ago

A square coil ℓ = 2cm on a side with 30 turns rotates in a uniform magnetic field, B~ = B0zˆ = 0.1Tˆz, such that the normal of t

kow [346]

Answer:

a) 1.2*10^{-3}cos(1.25t)

b) 0.49mV

Explanation:

a) The coil rotates periodically with period T. Hence, we can write the variation of the magnetic flux with a sinusoidal function, and with max flux NAB. Thus, we have that:

$\Phi_B(t)=NABcos(\omega t)\\\\\omega=\frac{2\pi}{T}=1.25\frac{rad}{s}\\\\A=l^2=(0.02m)^2=4*10^{-4}m^2\\\\B=0.1T\\\\\Phi_B(t)=1.2*10^{-3}cos(1.25 t) W$

where we have used the values given by the information of the problem for N B and A.

the emf is given by:

$emf=-\frac{d\Phi_B}{dt}=-NBA\omega sin(\omega t)\\\\emf(t=12.5s)=-(30)(0.1T)(4*10^{-4})(1.25\frac{rad}{s})sin(1.25*12.5)=1.49*10^{-4}V=0.49mV$

hope this helps!!

5 0

3 years ago

Explain Energy Transformation using the image below and how the Law of Conservation of Energy is maintained.

Karolina [17]

The chemical energy of petrol is converted to heat energy on combustion. The heat energy is converted to kinetic energy by the use of internal combustion engines in vehicles. The law of conservation of energy is maintained in each process.

<h3>What is kinetic energy?</h3>

The kinetic energy of an object is associated with its motion. It can be related to the mass and velocity as

K.E = 1/2 mv²

Given is a diagram of energy conversion due to combustion.

The chemical energy of petrol is converted to heat energy on combustion. The heat energy is converted to kinetic energy by the use of internal combustion engines in vehicles.

The law of conservation of energy states that the energy can neither be created nor destroyed. It can be only converted to one form to the other.

In the given process, the mass decreases but energy remains the same in all forms of energy.

Hence, the law of conservation of energy is maintained in each process

Learn more about kinetic energy.

brainly.com/question/12669551

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8 0

2 years ago