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AfilCa [17]
3 years ago
14

A 2kg block of which material would require 450 joules of thermal energy to increase its temperature by 1 degree Celsius?

Physics
1 answer:
12345 [234]3 years ago
7 0

The block is made of A) Tin, as its specific heat capacity is 0.225 J/(g^{\circ}C)

Explanation:

When an amount of energy Q is supplied to a sample of material of mass m, the temperature of the material increases by \Delta T, according to the following equation :

Q=mC_s \Delta T

where  C_s is the specific heat capacity of the material.

In this problem, we have:

m = 2 kg = 2000 g is the mass of the unknown material

Q = 450 J is the amount of energy supplied to the block

\Delta T = 1^{\circ}C is the change in temperature of the material

Solving the equation for C_s, we can find the specific heat capacity of the unknown sample:

C_s = \frac{Q}{m \Delta T}=\frac{450}{(2000)(1)}=0.225 J/(g^{\circ}C)

And by comparing with tabular values, we can find that this value is approximately the specific heat capacity of tin.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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Two blocks are connected by a string over a pulley. The hanging block has a mass of 8-kg and the one on the plane has a mass of
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Answer:

Let f be force of friction on the blocks kept on inclined plane. T be tension in the string

For motion of block on the inclined plane in upward direction

T - m₁gsin40 - f = m₁a

f = μ m₁gcos40

For motion of hanging  block on  in downward direction

m₂g  - T = m₂ a

Adding to cancel T

m₂g - - m₁gsin40 -  μ m₁gcos40 = a ( m₁+m₂ )

a =   g (m₂ - - m₁sin40 -  μ m₁cos40) / ( m₁+m₂ )

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M₂ will go down and M₁ will go up with acceleration .

Explanation:

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3 years ago
According to Coulomb’s Law, the force between two charged objects is related to _____. the distance separating them the mass of
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The force between two charges objects is related to separation.


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3 years ago
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A spring has a 12 cm length. When a 200-g mass is hung from the spring, it extends to 27 cm. The hanging mass were pulled downwa
BartSMP [9]

Answer:

The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

(b) is correct option.

Explanation:

Given that,

Length = 12 cm

Mass = 200 g

Extend distance = 27 cm

Distance = 5 cm

Phase angle =0°

We need to calculate the spring constant

Using formula of restoring force

F=kx

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{200\times10^{-3}\times9.8}{(27-12)\times10^{2}}

k=13.06\ N/m

We need to calculate the time period

Using formula of time period

T=2\pi\sqrt{\dfrac{m}{k}}

Put the value into the formula

T=2\pi\sqrt{\dfrac{0.2}{13.6}}

T=0.777\ sec

At t = 0, the maximum displacement was 5 cm

So, The equation of the time-dependent function of the position

x(t)=A\cos(\omega t)

Put the value into the formula

x(t)=5\cos(2\pi\times f\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{T}\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{0.777}\times t)

x(t)=5\cos(8.08t)

Hence, The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

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4 years ago
a bungee jumper momentarily comes to rest at the bottom of the dive before he springs back upward. at that moment, is the bungee
barxatty [35]

Answer:

Explanation:

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3 years ago
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