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STALIN [3.7K]
3 years ago
14

Andy puts some pieces of paper on a drum and then hits the drum with a drumstick. What observation supports the idea that sound

is produced by vibration?
Chemistry
2 answers:
Shkiper50 [21]3 years ago
8 0

Though she hits the drum, the papers on the drum also vibrate.

This is due to the fact that when she hits the drum, the shock waves created by the hitting travel through the skin of the drum and radiate outwards. When they encounter the papers,  some of this energy is transmitted to the papers and the papers also vibrate.


Zinaida [17]3 years ago
7 0

Answer:

The vibration of the pieces of paper.

Explanation:

After Andy hits the drum with a drumstick a force is applied on the drum, this produces that the drumhead vibrates generating sound. This vibration is then transmitted to the pieces of paper which also vibrate.

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7 0
3 years ago
5. Azulene is a beautiful blue hydrocarbon. If 0.106 g of the compound is burned in oxygen, 0.364 g of CO2 and 0.0596 g of H2O a
max2010maxim [7]

<u>Answer:</u> The empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.364g

Mass of H_2O=0.0596g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

<u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.364 g of carbon dioxide, \frac{12}{44}\times 0.364=0.0993g of carbon will be contained.

<u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0596 g of water, \frac{2}{18}\times 0.0596=0.0067g of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.0993g}{12g/mole}=0.00828moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.0067g}{1g/mole}=0.0067moles]

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0067 moles.

For Carbon = \frac{0.00828}{0.0067}=1.23\approx 1

For Hydrogen = \frac{0.0067}{0.0067}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 1

The empirical formula for the given compound is CH

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 128.2 g/mol

Mass of empirical formula = 13 g/mol

Putting values in above equation, we get:

n=\frac{128.2g/mol}{13g/mol}=9.86\approx 10

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(1\times 10)}H_{(1\times 10)}=C_{10}H_{10}

The general formula of an alkane is C_nH_{(2n+2)}, where n = any natural number

Here, n = 10 and it does not satisfy being an alkane

Hence, the empirical and molecular formula for the given organic compound is CH and C_{10}H_{10} and it is not an alkane.

7 0
3 years ago
5. What must happen for a seed to emerge from the soil as a seedling?​
jeka94

Answer:

It must have sunlight and water and neutrants and be fertilized

Explanation:

6 0
3 years ago
How many moles of atoms are in 6.00 g of 13C?
Lyrx [107]

Answer: 0.462 moles

Explanation: 13C indicates an isotope of carbon and its mass number is 13. It means the mass of 1 mol of 13C is 13 gram.

The question asks to calculate the number of atoms present in 6.00 grams of 13C.

To calculate the number of moles we divide the given grams by the mass of 1 mol of the element. The set could be shown easily using dimensional analysis as:

6.00gram(\frac{1mol}{13gram})

= 0.462 moles

So, there will be 0.462 moles of atoms in 6.00 grams of 13C.

4 0
3 years ago
Read 2 more answers
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