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tekilochka [14]
2 years ago
6

If a gaseous mixture is made by combining 2.74 g Ar 2.74 g Ar and 4.90 g Kr 4.90 g Kr in an evacuated 2.50 L container at 25.0 ∘

C, 25.0 ∘C, what are the partial pressures of each gas, P Ar PAr and P Kr , PKr, and what is the total pressure, P total , Ptotal, exerted by the gaseous mixture?
Chemistry
1 answer:
krok68 [10]2 years ago
7 0

Answer:

Hfhfj

Explanation:

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A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it r
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Answer:

the final mole of the flexible container = 12.92 moles

Explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

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Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,

n= \dfrac{V_2*n_1}{V_1}

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3 years ago
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morpeh [17]

Answer:

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Explanation:

Can you show me the rest of the question? I can not see it. Also, I know this is multiple choice fill in the blanks so I might be wrong. I hope that this helped though. This took a lot of research. The websites I used are commented down below. |

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Answer:

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