Answer:
I think it's the last one
Explanation:
good luck
Explanation:
here,load=100N
effort=200N
distance travelled by load=2cm
distance travelled by effort=10cm
Now, output work=L*Ld
=100*2
=200g
Again,
input work =E*Ed
200*10
2000j
again, efficiency = output work/input work*100%
200/2000*100%
=10%
please don't forget to write symbol
Explanation:
Let magnitude of the two forces be x and y.
Resultant at right angle R1= √15N) and at
60 degrees be R2= √18N.
Now, R1 = √(x² + y²) = √15,
R2= √(x² + y² +2xycos50) = √18.
So x² + y² = 15,
and x² + y² + 1.29xy = 18,
therefore 1.29xy = 3,
y = 3/1.29x.
y = 2.33/x
Now, x2 + (2.33/x)2 = 15,
x² + 5.45/x² = 15
multiply through by x²
x⁴ + 5.45 = 15x²
x⁴ - 15x2 + 5.45 = 0
Now find the roots of the equation, and later y. The two values of x will correspond to the
magnitudes of the two vectors.
Good luck
What’s the weight and how high is the clif
<span>Use Charles' Law:
v1/T1 = v2/T2
88.2/(273+35) = v2/(273+155)
where v2 is the new volume.
I hope this helps!!!</span>
