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3 years ago

If your friend drops a chocolate bar to you from a height of 5.0 m above your hands,

Physics

1 answer:

Sladkaya [172]3 years ago

6 0

Answer:

Explanation:

Using the equation of motion S = ut+1/2gt² to solve the problem where;

u is the initial velocity of the chocolate = 0m/s

t is the time taken

g is the acceleration due to gravity = 9.81m/s²

S is the height of fall = 5.0m

Substituting the given parameter into the formula to get the time t we have;

5 = 0(t)+1/2(9.81)t²

5 = 4.905t²

t² = 5/4.905

t² = 1.019

t = √1.019

t = 1.009 secs

Hence it will take 1.01 secs for me to catch the chocolate bar

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2 years ago

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1 year ago

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2 years ago

Suppose 8.50 ✕ 10^5 J of energy are transferred to 1.63 kg of ice at 0°C. The latent heat of fusion and specific heat of water a

PolarNik [594]

Answer:

(a) 5.43 x 10⁵ J

(b) 3.07 x 10⁵ J

Explanation:

(a)

$L_{f}$ = Latent heat of fusion of ice to water = 3.33 x 10⁵ J/kg

m = mass of ice = 1.63 kg

$Q_{f}$ = Energy required to melt the ice

Energy required to melt the ice is given as

$Q_{f}$ = m $L_{f}$

$Q_{f}$ = (1.63) (3.33 x 10⁵)

$Q_{f}$ = 5.43 x 10⁵ J

(b)

E = Total energy transferred = 8.50 x 10⁵ J

Q = Amount of energy remaining to raise the temperature

Using conservation of energy

E = $Q_{f}$ + Q

8.50 x 10⁵ = 5.43 x 10⁵ + Q

Q = 3.07 x 10⁵ J

(c)

T₀ = initial temperature = 0°C

T = Final temperature

m = mass of water = 1.63 kg

c = specific heat of water = 4186 J/(kg °C)

Q = Amount of energy to raise the temperature of water = 3.07 x 10⁵ J

Using the equation

Q = m c (T - T₀)

3.07 x 10⁵ = (1.63) (4186) (T - 0)

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3 years ago

The spin-drier of a washing machine revolving at 900.RPM slows down uniformly to 300.RPM while making 60. revolutions. Find the

jeyben [28]

<h2>Answer:</h2>

Acceleration is -10.57 rad/s²

Time is 6 seconds

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s=60 revolutions= 377 rad

v²= u²+ 2as

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a = v²-u² / 2s

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Using 1st equation of motion

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Putting the values

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3 years ago