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cestrela7 [59]
4 years ago
12

If your friend drops a chocolate bar to you from a height of 5.0 m above your hands,

Physics
1 answer:
Sladkaya [172]4 years ago
6 0

Answer:

<h3>1.01 s</h3>

Explanation:

Using the equation of motion S = ut+1/2gt² to solve the problem where;

u is the initial velocity of the chocolate = 0m/s

t is the time taken

g is the acceleration due to gravity = 9.81m/s²

S is the height of fall = 5.0m

Substituting the given parameter into the formula to get the time t we have;

5 = 0(t)+1/2(9.81)t²

5 = 4.905t²

t² = 5/4.905

t² = 1.019

t = √1.019

t = 1.009 secs

<em>Hence it will take 1.01 secs for me to catch the chocolate bar</em>

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3 years ago
What is the period of a simple pendulum 47 cm long (a) on the Earth, and ( b) when it is in a freely falling elevator?
Liula [17]

Answer:

a)1.37 s

b)∞ ( Infinite)

Explanation:

Given that

L= 47 cm              ( 1 m =100 cm)

L= 0.47 m

a)

On the earth :

Acceleration due to gravity = g

We know that time period of the simple pendulum given as

T=2\pi\sqrt{ \dfrac{L}{g_{{eff}}}

Here

g_{eff}= g

Now by putting the values

T=2\pi \times\sqrt{ \dfrac{0.47}{9.81}}

T=1.37 s

b)

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When elevator is falling freely then

g_{eff}= 0            ( This is case of weightless motion)

Therefore

T=2\pi\sqrt{ \dfrac{L}{0}

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6 0
4 years ago
What are the precaution you take when you are carrying out experiment on kirchhoffs law​
sdas [7]

Answer:

The precautions to be followed for performing kirchoff law experiment are:-

  1. check that all the connections inside the arrangement are tight and clean.
  2. check that the terminals of the resistances  are nicely attached.
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These are the basic precautions that must be kept in mind before executing kirchoff law experiment.

4 0
3 years ago
1. A hot air balloon weighing 30 N is tied to the ground by a string to prevent
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Answer:

a) FB = 260 [N]

b) FT = 230 [N]

Explanation:

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The buoyant force acts upward as it causes the balloon to tend to float, the weight of the balloon tends to lower the balloon and the downward tension force does not allow the balloon to float

The buoyant force is defined by the following equation:

FB = Ro*V*g

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FB = Buoyant force [N]

Ro = density of the air = 1.3 [kg/m^3]

V = volume of the balloon = 20 [m^3]

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Now we do a sum of forces equal to zero in the y-axis

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260 - 30 = FT

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3 years ago
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