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Complete Question:
a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.
Answer in units of m/s2
b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under
these new conditions.
Answer in units of m/s2
Answer:
a. 2.875m/s²
b. 3.172m/s²
Explanation:
a. The formula for centripetal acceleration = (speed²) ÷ radius
Centripetal acceleration = (5.7m/s)²÷ 11.3m
Centripetal acceleration = 2.875m/s²
b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.
Centripetal acceleration ( acceleration x) = 2.875m/s²
Increase in the speed rate ( acceleration n) = 1.34m/s²
Magnitude of acceleration = √a²ₓ + a²ₙ
=√( 2.875m/s²)²+ (1.34m/s²)²
= √ 10.06m/s²
= 3.172m/s²
Answer:
A goal keepee catering the ball in time is answer
Answer:
C. turtles with genes for long necks had a better chance of surviving to reach reproductive age.
Explanation:
The turtles that had long necks were more fit to the environmnet in which they were lovated and were able to grow larger and have more reproductive time because of their ability to feed on grass and small shrubs, this helped them always haev food available, and made them the dominant gene eventually.
Answer:
= 0.5 m/s²
Explanation:
- According to Newton's second law of motion, the resultant force is directly proportion to the rate of change of linear momentum.
Therefore;<em> F = ma , where F is the Force, m is the mass and a is the acceleration.</em>
<em>Thus; a = F/m</em>
<em>but; F = 5 N, and m = 10 kg</em>
<em> a = 5 /10</em>
<u>= 0.5 m/s²</u>
