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timofeeve [1]
3 years ago
13

A ball on a string is swung around in a horizontal circle. The centripetal force

Physics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

0.60 N, towards the centre of the circle

Explanation:

The tension in the string acts as centripetal force to keep the ball in uniform circular motion. So we can write:

(1)

where

T is the tension

m = 0.015 kg is the mass of the ball

is the angular speed

r = 0.50 m is the radius of the circle

We know that the period of the ball is T = 0.70 s, so we can find the angular speed:

And by substituting into (1), we find the tension in the string:

And in an uniform circular motion, the centripetal force always points towards the centre of the circle, so in this case the tension points towards the centre of the circle.

Explanation:

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A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
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Answer:

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Explanation:

Given;

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radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

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The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

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