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2 years ago

A ball on a string is swung around in a horizontal circle. The centripetal force

Physics

1 answer:

ivanzaharov [21]2 years ago

5 0

Answer:

0.60 N, towards the centre of the circle

Explanation:

The tension in the string acts as centripetal force to keep the ball in uniform circular motion. So we can write:

(1)

where

T is the tension

m = 0.015 kg is the mass of the ball

is the angular speed

r = 0.50 m is the radius of the circle

We know that the period of the ball is T = 0.70 s, so we can find the angular speed:

And by substituting into (1), we find the tension in the string:

And in an uniform circular motion, the centripetal force always points towards the centre of the circle, so in this case the tension points towards the centre of the circle.

Explanation:

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A rocket accelerates upward from rest at a rate of 5 m/s^2. At a height of 1000m, the engines burn out and it coasts the rest of

laila [671]

Answer:

Explanation:

Given

acceleration of rocket(a) $=5 m/s^2$

At h=1000 m rocket burn out

$v^2-u^2=2as$

$v^2-0=2\times 5\times 1000$

$v=\sqrt{10^4}=100 m/s$

(b) time to reach v=100 m/s

v=u+at

$100=0+5\times t$

$t=\frac{100}{5}=20 s$

(c)Rocket maximum altitude

$v^2-u^2=2as$

here u=100 m/s

v=0

$a=9.8 m/s^2$

$s=\frac{v^2}{2g}$

$s=\frac{100^2}{2\times 9.8}$

[tex]s=510.204

Therefore maximum altitude=510.204+1000=1510.204 m

7 0

2 years ago

A person is sitting with one leg outstretched and stationary, so that it makes an angle of θ = 27.5° with the horizontal, as the

dangina [55]

here we will use the torque balance about the knee joint

here we can say that

$\tau_g = \tau_m$

here torque due to weight is given as

$\tau_g = 40.1 cos\theta*(l_1 + l_2)$

$\tau_g = 40.1 cos27.5*(0.105 + 0.150)$

$\tau_g = 9.07 Nm$

now torque due to applied force of muscle

$\tau_m = M*sin\alpha * l_1$

$\tau_m = M*sin30* 0.105$

now by torque balance we will have

$9.07 = M*0.5*0.105$

$M = 173 N$

so here the magnitude of m will be 173 N

7 0

2 years ago

Do all of them please and explain

kondaur [170]

At 305 and 309 it was negative because it is going down

at 300 and 301 and 305 it was positive because its going up

at 302/303/304/306/309 she wasn't accelerating at all because it is staying the same

5 0

2 years ago

Read 2 more answers

La luz roja visible tiene una longitud de onda de 680 nanómetros (6,8 x 10-7 m). La velocidad de la luz es de 3.0 x108 m / s. ¿C

Lina20 [59]

Answer:

Frequency, $f=4.41\times 10^{14}\ Hz$

Explanation:

Visible red light has a wavelength of 680 nanometers (6.8 x 10⁻⁷ m). The speed of light is 3.0 x 10 ⁸ m / s. What is the frequency of visible red light?

It is given that,

Wavelength of a visible red light is, $\lambda=6.8\times 10^{-7}\ m$

Speed of light is, $c=3\times 10^8\ m/s$

We need to find the frequency of visible red light. It can be calculated using below relation.

$c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{6.8\times 10^{-7}}\\\\f=4.41\times 10^{14}\ Hz$

So, the frequency of visible red light is $4.41\times 10^{14}\ Hz$ .

3 0

2 years ago

Two identical positive charges are placed near each other. At the point halfway between the two chargesTwo identical positive ch

Nitella [24]

Answer:The electric field is zero and the potential is positive.

Explanation:

Two identical positive charges are separated by a certain distance and midway between charges two identical positive charges are placed near each other.

So the Electric field at midway is zero because the electric field due to both charges add up to give zero electric field.(because they point in opposite direction)

Potential is scalar quantity and charges are positive so they add up to give potential.

7 0

2 years ago