Question

Help please! -A compound contains 0.013 moles of carbon, 0.039 moles of hydrogen and 0.0065 moles of oxygen. Determine the empirical
formula.
A) C2H601
B) C3H501
C) C4H12O2
D) CHO

Answer 1

A) C2H6O1

To find the emperical formula, divide each mole value by the smallest

For carbon, 0.013/0.0065 = 2

For hydrogen, 0.038/0.0065= 6

For oxygen, 0.0065/0.0065= 1

Emperical formula = C2H6O1

Answer 2

Answer:

C2H6O1

Explanation:

Empirical formula means to express the ratio of the number of atoms , i.e to identify which of the three elements appears with the smallest number of atoms in the formula, and then to get the rate of the atoms belonging to other species in respect with this one. In this molecule Oxygen shows the smallest number of moles (0.0065)  (O1)

To see how many moles of carbon correspond to 1 mole of Oxygen, divide 0.013 moles of C to 0.0065 moles of Oxygen:  0.013/0.0065 =2 Therefore for each mole of Oxygen you have two moles of C (C2)

To see how many moles of Hydrogen correspond to 1 mole of Oxygen, divide 0.039 moles of H to 0.0065 moles of Oxygen:  0.039/0.0065 =6 Therefore for each mole of Oxygen you have six moles of H  (H6)

The empirical formula is C2H6O1