Answer:
The focal length fe of the eyepiece is <em>2.86 cm</em>
Explanation:
Since we are given the telescope's magnification and the length of the tube, we can use the expressions
<em>M = f_o/fe (1)</em> and
<em>l = f_o + fe (2)</em>
where
- M is the telescope's magnification
- l is the length of the tube
- fe is the focal length of the eye-piece
Rearranging equation (2) to make f_o the subject of the formula, we get
<em>f_o = l - fe</em>
Substituting the above equation into equation (1) we get
<em>M = (l - fe)/fe ⇒ fe = l/(M +1)</em>
<em> ⇒ fe = 60/(20 + 1)</em>
⇒ <em>fe = 2.86 cm</em>
Answer:
Δp = -2 p₀
Explanation:
The momentum is defined by
p = m v
In this case we write the initial and final momentum, we take as positive the direction towards the wall.
p₀ = m v
p_f = m (-v)
the negative sign is because the car is bouncing off the wall
the change of the moment is
Δp = p_f - p₀
Δp = - m v - m v
Δp = -2 mv
Δp = -2 p₀
we see that the change of moment is twice the moment, in the attachment we can see the vectors of these changes and the sign indicates the direction of the change at the moment
Answer:
Density = 11.11 kg/m³
Explanation:
Given the following data;
Mass = 40 kg
Dimensions = 30×4×3 = 360 cm³ to m³ = 360/100 = 3.6 m³
Thus, volume = 3.6 m³
Now, we can find the density;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;

Substituting into the equation, we have;
Density = 40/3.6
Density = 11.11 kg/m³
Answer:
same but from what i know is the newtons thingy
Explanation:
hope that helps!
There are several information's of immense importance already given. Let us now focus on the problem in hand.
Pressure = Force/Area
Area = 58.8 cm^2
= 0.0058 m2
Then
Pressure = (12 * 9.8)/0.0058
= 20275 Pascals
= 2 Pa
The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your desired help.