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2 years ago

Earth is like a bar magnet. What does this mean about its magnetic poles?

Physics

2 answers:

Dmitrij [34]2 years ago

8 0

Answer:

the answer is b

Explanation:

Anit [1.1K]2 years ago

6 0

B a bar magnet has a north and a south pole.

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Suppose that the separation between two speakers A and B is 4.80 m and the speakers are vibrating in-phase. They are playing ide

Hatshy [7]

Answer:

$X=8.44m$

Explanation:

From the question we are told that

Distance b/w A&B $x=4.80m$

Frequency $f=134Hz$

Sound speed $v=343m/s$

Generally the equation for wavelength is mathematically given as

$\lambda=v/f$

$\lambda/2=1/2*v/f$

$\lambda/2=1/2*\frac{343}{135}$

$\lambda/2=1.27037037$

Generally the destructive interference X is mathematically given by

$\sqrt{4.8^2 +X^2} -X=1.27037037\\$

$23.04+BC^2=X^2+1.613+2.54*X$

Therefore the destructive interference is

$X=8.44m$

4 0

2 years ago

What is the difference between velocity and speed??

tatiyna

Velocity is a vector quantity i.e. it has both magnitude and direction
Speed is a scalar quantity i.e. it has only magnitude

5 0

2 years ago

Read 2 more answers

3. The main difference between speed and velocity involves

Zinaida [17]

The difference between them is that
velocity is the speed with a direction, whereas speed does not have a direction.

8 0

2 years ago

Riders on a ferris wheel move in a circle with a speed of 4.0 m/s. As they go around, they

Vanyuwa [196]

Answer: D = 16m

Explanation: given values: a = 2 m/s2, v = 4 m/s
In this case we have to determine the diameter of the Ferris wheel.
Diameter of circle is given as: D = 2.r.
First we have to find radius of wheel. The best way to find that is using the centripetal acceleration equation: a = v2/r
Plug in values in above equation to find radius: 2 m/s2 = (4 m/s)2/r 2 m/s2 = (16 m2/s2)/r r = (16 m2/s2)/2 m/s2
r = 8.0m
Diameter of Ferris wheel is:
D = 2.r.
D = 2.8m
D = 16m

6 0

2 years ago

A ball of mass m is thrown straight upward from ground level at speed v0. At the same instant, at a distance D above the ground,

n200080 [17]

Answer:

a. $t = \frac{v_{0} +/- \sqrt{v_{0} ^{2} - gD} }{g}$ b. D = v₀²/2g

Explanation:

Here is the complete question

A ball is thrown straight up from the ground with speed v₀ . At the same instant, a second ball is dropped from rest from a height D , directly above the point where the first ball was thrown upward. There is no air resistance

Find the time at which the two balls collide.

Express your answer in terms of the variables D ,v₀ , and appropriate constants..

t = ?!

Part B

Find the value of D in terms of v₀ and g so that at the instant when the balls collide, the first ball is at the highest point of its motion.

Express your answer in terms of the variables v₀ and g .

D =?!

Solution

The distance moved by the ball dropped from distance,D with velocity v₀, H₁ = D - (v₀t - gt²/2) = D + v₀t + gt²/2.

The distance moved by the ball thrown straight upward with velocity v₀ is H₂ = v₀t - gt²/2.

The two balls collide when their vertical distances are equal. That is H₁ = H₂

So, D - v₀t + gt²/2 = v₀t - gt²/2

Collecting like terms

D + gt²/2 + gt²/2 = v₀t + v₀t

D +gt² = 2v₀t

gt² - 2v₀t + D = 0.

Using the quadratic formula,

$t = \frac{-(-2v_{0} ) +/- \sqrt{(-2v_{0} )^{2} - 4 X g XD} }{2g} = \frac{2v_{0} +/- \sqrt{4v_{0} ^{2} - 4gD} }{2g} = \frac{v_{0} +/- \sqrt{v_{0} ^{2} - gD} }{g}$

B. At its highest point, the velocity of the first ball, v = 0. Using v² = u² - 2gs where s = highest point of first ball when they collide and u = v₀.

0 = v₀² - 2gs

s = v₀²/2g.

Also, the time it takes the first ball to reach its highest point is gotten from v = u - gt. At highest point, v = 0 and u = v₀. So,

0 = v₀ - gt₀

t₀ = v₀/g

Also H = s₁ + s where s₁ = distance moved by second ball in time t₀ for collision = v₀t₀ - gt₀²/2.

So, H = v₀t₀ - gt₀²/2 + v₀²/2g = v₀(v₀/g) - g(v₀/g)²/2 + v₀²/2g = v₀²/2g - v₀²/2g + v₀²/2g = v₀²/2g

6 0

2 years ago