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Blizzard [7]
3 years ago
7

What is the velocity of a 0.5-kg ball that has a momentum of 3 kg.m/s?

Chemistry
1 answer:
maria [59]3 years ago
3 0

Answer:

6m/s

Explanation:

Data obtained from the question include:

Mass = 0.5kg

Momentum = 3 kg.m/s

Velocity =.?

Momentum is simply the product of mass and velocity as shown by the equation below:

Momentum = Mass x Velocity

Velocity = Momentum /mass

Velocity = 3kg.m/s / 0.5kg

Velocity = 6m/s

Therefore, the velocity of the ball is 6m/s

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HELP ASAP !!!!!
Anna35 [415]

Answer:

Explanation:

Take a random sample of nuts from the jar.  Let's take two handfuls, after shaking the jar and mixing the nuts thoroughly.  Separate the nuts into almonds and cashews.  Count each pile, then do the following calculation (these numbers are random, for example only).

                <u> Count</u>   <u>Percentage %</u>

Almonds       38        (38)/(87)x100

Cashews      <u> 49</u>         49/87x100

                      87          87/87 = 100%

Ratio of Almonds to Cashews:  <u>38/49</u>

3 0
2 years ago
How many electrons are in their outer shell?
quester [9]
Is there an attachment because it depends on the element.
5 0
3 years ago
How an ionic compound made up of charged particles can be electrically neutral
finlep [7]

Answer:

Explanation:

Ionic compounds are electrically neutral because the charges of the cations and anions that make up the compound cancel each other out. In the case of salt for example, sodium has a charge of positive one, and chloride has a charge of negative one. Together, they neutralize the compound.

5 0
3 years ago
The concentration of sugar in Coke is approximately 10%, or 100 ppt. If you drink
masya89 [10]

Answer:

35.5g of sugar

Explanation:

To solve this question we must assume the density of coke = Density of water = 1g/mL

Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:

355g * (10/100) = 35.5g of sugar

<em>10/100 = 10%</em>

7 0
3 years ago
One of the reactions in a blast furnace used to reduce iron is shown above. How many grams of Fe2O3 are required to produce 15.5
Salsk061 [2.6K]

Answer : The correct option is, (b) 22.1 g

Solution : Given,

Mass of iron = 15.5 g

Molar mass of iron = 56 g/mole

Molar mass of Fe_2O_3 = 160 g/mole

First we have to calculate the moles of iron.

\text{Moles of Fe}=\frac{\text{Mass of Fe}}{\text{Molar mass of Fe}}=\frac{15.5g}{56g/mole}=0.276moles

Now we have to calculate the moles of Fe_2O_3.

The balanced reaction is,

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2

From the balanced reaction, we conclude that

As, 2 moles of iron obtained from 1 mole of Fe_2O_3

So, 0.276 moles of iron obtained from \frac{0.276}{2}=0.138 mole of Fe_2O_3

Now we have to calculate the mass of Fe_2O_3

\text{Mass of }Fe_2O_3=\text{Moles of }Fe_2O_3\times \text{Molar mass of }Fe_2O_3

\text{Mass of }Fe_2O_3=(0.138mole)\times (160g/mole)=22.08g=22.1g

Therefore, the amount of Fe_2O_3 required are, 22.1 grams.

6 0
3 years ago
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