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2 years ago

What is diffusion ,??

2 answers:

7 0

Diffusion is the net movement of anything generally from a region of higher concentration to a region of lower concentration. Diffusion is driven by a gradient in Gibbs free energy or chemical potential.

UNO [17]2 years ago

4 0

Diffusion is a process that results from the random motion of molecules and results in a net movement of matter from a high-concentration region to a low-concentration zone.

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3.47 g of the hydrated "double salt", ammonium iron (II) sulfate hexahydrate, FeSO4(NH4)2SO4*6H2O was dissolved in 200. mL of wa

Ostrovityanka [42]

Answer:

1.4 × 10^-4 M

Explanation:

The balanced redox reaction equation is shown below;

5Fe2+ + MnO4- + 8H+ --> 5Fe3+ +Mn2+ + 4H2O

Molar mass of FeSO4(NH4)2SO4*6H2O = 392 g/mol

Number of moles Fe^2+ in FeSO4(NH4)2SO4*6H2O = 3.47g/392g/mol = 8.85 × 10^-5 moles

Concentration of Fe^2+ = 8.85 × 10^-5 moles × 1000/200 = 4.425 × 10^-4 M

Let CA be concentration of Fe^2+ = 4.425 × 10^-4 M

Volume of Fe^2+ (VA)= 20.0 ml

Let the concentration of MnO4^- be CB (the unknown)

Volume of the MnO4^- (VB) = 12.6 ml

Let the number of moles of Fe^2+ be NA= 5 moles

Let the number of moles of MnO4^- be NB = 1 mole

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB= CAVANB/VBNA

CB= 4.425 × 10^-4 × 20 × 1/12.6 × 5

CB = 1.4 × 10^-4 M

7 0

3 years ago

Which element has the same number of energy levels as aluminum (Al) and the same number of valence electrons as calcium (Ca)? A.

Rudik [331]

The answer to this question would be: <span>D. Magnesium

The </span><span>number of energy levels of aluminum is 3 which was why it was put on the 3rd row. The valence of calcium is 2 which is why it was put in the 2nd column. If you look at the periodic table, the answer should be clear that it was magnesium.</span>

7 0

3 years ago

If 45.0 liters of oxygen is measured at 24.0C, what would be its volume at standard temperature?

nika2105 [10]

The volume of the oxygen gas at standard temperature is 41.36 liters.

The given parameters;

<em>initial volume of oxygen, V₁ = 45 L</em>
<em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
<em>standard temperature, T₂ = 0 ⁰C = 273 K</em>

<em />

The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;

$\frac{V_1}{T_1} = \frac{V_2}{T_2} \\\\V_2 = \frac{V_1 T_2}{T_1} \\\\V_2 = \frac{45 \times 273}{297} \\\\V_2 = 41.36 \ L$

Thus, the volume of the oxygen gas at standard temperature is 41.36 L.

Learn more here:brainly.com/question/16927784

6 0

3 years ago

Reasons and how we arrange elements according to their positions in the electrochemical series

Sladkaya [172]

Answer:

$mile please :)

Explanation:

$mile please :)

6 0

3 years ago

The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc

melisa1 [442]

<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>

To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

= 0.3869 J/g°C

= 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0

3 years ago

What is diffusion ,?? ​

What is diffusion ,??