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MrRa [10]
3 years ago
13

For the formula shown, how many sulfur atoms are represented?

Chemistry
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

i also need the is question help!!!

Explanation:

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What type of bond exists between the atoms in a molecule of N2?
vivado [14]

Answer:

covalent bonds

Explanation:

Nitrogen atoms will form three covalent bonds (also called triple covalent) between two atoms of nitrogen because each nitrogen atom needs three electrons to fill its outermost shell.

(if it is still confusing i have another way of explaining so jus let me know :)

6 0
3 years ago
How do i turn into a mermaid
kenny6666 [7]
Brush your hair with a fork and sing a lot
7 0
3 years ago
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A chemist dissolves 581.1mg of pure perchloric acid in enough water to make up 150 ml of solution. Calculate the pH of the solut
algol [13]

<u>Answer:</u> The pH of the solution is 1.41

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of perchloric acid = 581.1 mg = 0.5811 g   (Conversion factor:  1 g = 1000 mg)

Molar mass of perchloric acid = 100.5 g/mol

Volume of solution = 150 mL

Putting values in above equation, we get:

\text{Molarity of perchloric acid}=\frac{0.5811\times 1000}{100.5\times 150}\\\\\text{Molarity of perchloric acid}=0.0385M

1 mole of perchloric acid produces 1 mole of H^+ ions and 1 mole of ClO_4^- ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.0385M

Putting values in above equation, we get:

pH=-\log (0.0385)=1.41

Hence, the pH of the solution is 1.41

6 0
3 years ago
Calcium oxide (CaO) forms when an atom of calcium loses two electrons, giving it a +2 charge and an atom of oxygen picks up two
OLEGan [10]
Its C

An ionic bonded compound as the bond is formed from a metal and a non metal plus its a strong electrostatic attraction between 2 or more elements 

hope that helps
6 0
3 years ago
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During a titration a student found that 20.0cm3 of sodium carbonate solution
vlada-n [284]

Answer: The concentration of Na_2CO_3 required is 0.349mol/dm^3

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of HNO_3 = 1

M_1 = molarity of HNO_3 solution = 0.500 mol/dm^3

V_1 = volume of  HNO_3 solution = 27.9cm^3

n_2 = acidity of Na_2CO_3 = 2

M_1 = molarity of Na_2CO_3 solution =?

V_1 = volume of  Na_2CO_3 solution =  20.0cm^3  

Putting in the values we get:

1\times 0.500\times 27.9=2\times M_2\times 20.0

M_2=0.349mol/dm^3

Therefore, concentration of Na_2CO_3 required is 0.349mol/dm^3

4 0
3 years ago
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