Question

A kangaroo jumps straight up with an initial vertical velocity of 2.4\,\dfrac{\text{m}}{\text{s}}2.4 sm​ 2, point, 4, space, start fraction, m, divided by, s, end fraction. We want to find the maximum height of the jump.

Answer 1

Answer:

it can jump upto maximum height of 0.29 m

Explanation:

Initial velocity of the Kangaroo when it jumps upwards is given as

$v_i = 2.4 m/s$

final velocity of the kangaroo is given as

$v_f = 0$

now we know that acceleration is due to gravity

$a = -g$

now in order to find maximum height we know that we can use kinematics equation

$v_f^2 - v_i^2 = 2a d$

$0 - 2.4^2 = 2(-9.81) d$

$d = 0.29 m$

so it can jump upto maximum height of 0.29 m